Understanding Divisibility and Division

The video tutorial guides viewers through solving a division problem by finding a missing digit. It starts by setting up the problem, where a number greater than 700 is divided by a single digit to yield a two-digit quotient. The tutorial explains that the divisor must be 8 or 9, and through divisibility rules, it is determined to be 9. The sum of the digits must be divisible by 9, leading to the conclusion that the missing digit is 6. Thus, the division problem is 765 divided by 9, resulting in 85.

What is the initial step suggested in the video to solve the problem?

• Pause the video and guess the answer

• Use a calculator to find the answer

• Ask a friend for help

• Skip to the end of the video

Tags

CCSS.5.NBT.B.6

CCSS.6.NS.B.2

Why must the divisor be greater than seven in the given problem?

• Because the divisor is a prime number

• Because the result is a three-digit number

• Because the result is a two-digit number

• Because the divisor is always greater than the dividend

Tags

CCSS.4.OA.B.4

Which number is ruled out as a possible divisor based on divisibility rules?

• Seven

• Ten

• Eight

• Nine

Tags

CCSS.4.OA.B.4

What is the divisibility rule for nine?

• A number is divisible by nine if it is a multiple of three

• A number is divisible by nine if it ends in nine

• A number is divisible by nine if the sum of its digits is divisible by nine

• A number is divisible by nine if it is an even number

Tags

CCSS.2.NBT.B.7

What is the sum of the known digits in the problem before finding the missing digit?

• Ten

• Eleven

• Twelve

• Thirteen

Tags

CCSS.3.OA.D.9

What is the missing digit that makes the number divisible by nine?

• Seven

• Six

• Five

• Four

Tags

CCSS.3.OA.D.9