Complex Numbers and Radicals

This video tutorial explains how to multiply complex numbers by first converting negative radicands into imaginary numbers using the imaginary unit 'i'. It provides two examples demonstrating the process of rewriting complex numbers in terms of 'i', multiplying them, and simplifying the result using prime factorization. The tutorial emphasizes the importance of correctly handling imaginary numbers to achieve accurate results.

Why is it important to express complex numbers in terms of 'i' before multiplying?

• To ensure the product is real

• To avoid incorrect simplification

• To make calculations faster

• To convert them into fractions

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CCSS.HSN.CN.A.1

What is the first step in multiplying complex numbers with negative radicands?

• Add them together

• Express them in terms of 'i'

• Convert them into fractions

• Multiply the radicands directly

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CCSS.HSN.CN.A.2

In the first example, what is the correct product of the complex numbers?

• 3√15

• -3√15

• -3√5

• 3√5

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CCSS.HSN.CN.A.2

What is the prime factorization of 45 used in the first example?

• 3 * 3 * 5

• 2 * 3 * 5

• 5 * 5 * 3

• 2 * 2 * 5

Why is it unnecessary to multiply and then break down into factors again?

• It saves time

• It avoids errors

• It is redundant

• It is more accurate

In the second example, what is the initial expression for the square root of -14?

• √-14 * √1

• √14 * √-1

• √14 * √1

• √-14 * √-1

What is the result of multiplying the complex numbers in the second example?

• -2√14

• 2√14

• -2√21

• 2√21

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CCSS.HSN-VM.B.5A

CCSS.HSN-VM.B.5B

What is the prime factorization of 14 used in the second example?

• 2 * 7

• 3 * 5

• 5 * 7

• 2 * 3

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CCSS.HSN.CN.A.1

What is the value of i^2 used in both examples?

• 2

• 0

• -1

• 1

What is the final simplified form of the product in the second example?

• -2√14

• -2√21

• 2√21

• 2√14