
Understanding Conservative Vector Fields

Interactive Video
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Mathematics
•
11th Grade - University
•
Hard

Mia Campbell
FREE Resource
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10 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the main advantage of knowing a vector field is conservative when evaluating a line integral?
It requires more complex calculations.
It simplifies the calculation by making the integral path-independent.
It makes the integral path-dependent.
It has no effect on the calculation.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Under what condition is a vector field considered conservative?
When the vector field is closed.
When the partial derivative of P with respect to x equals the partial derivative of Q with respect to y.
When both P and Q are constants.
When the partial derivative of Q with respect to x equals the partial derivative of P with respect to y.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the example provided, what are the components of the vector field F?
P = x^2 + y^2 and Q = 2xy
P = 2x + 5y and Q = 5x - 3y
P = 3x + 4y and Q = 4x - 3y
P = 5x - 3y and Q = 2x + 5y
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you determine the potential function of a conservative vector field?
By subtracting Q from P.
By differentiating P with respect to y and Q with respect to x.
By adding P and Q directly.
By integrating P with respect to x and Q with respect to y.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the result of the line integral along a simple closed smooth oriented curve for a conservative vector field?
It is always negative.
It is always positive.
It is always zero.
It depends on the path taken.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the potential function derived from the example with P = 2x + 5y and Q = 5x - 3y?
f(x, y) = x^2 + 5xy - 3y^2 + K
f(x, y) = 2x^2 + 3xy - 5y^2 + K
f(x, y) = 5x^2 + 2xy - 3y^2 + K
f(x, y) = 3x^2 + 5xy - 2y^2 + K
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the significance of the constant K in the potential function?
It represents a variable that changes with x.
It is a constant of integration that does not affect the gradient.
It is a function of y only.
It is a function of x only.
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