Properties of Summation and Expressions

The video tutorial explains how to compute a complex summation by breaking it down into simpler parts using mathematical properties. It starts with given values for two separate summations and demonstrates how to apply properties to factor out constants and simplify the expression. The final calculation is performed using the given values, resulting in a sum of 573. The tutorial concludes with a brief summary of the process.

What are the given values for the summations of a sub i and b sub i?

• a sub i = 25, b sub i = 19

• a sub i = 133, b sub i = 133

• a sub i = 17, b sub i = 10

• a sub i = 10, b sub i = 17

Tags

CCSS.7.EE.A.1

How can the summation of 25 a sub i plus 19 b sub i be rewritten using properties?

• As a difference of two summations

• As a sum of two separate summations

• As a product of two summations

• As a single summation

Tags

CCSS.7.EE.A.1

What is the next step after rewriting the summation as a sum of two separate summations?

• Subtract the constants from the summations

• Multiply the summations by each other

• Add the constants to the summations

• Factor out the constants from the summations

Tags

CCSS.7.EE.A.1

Which property allows us to factor out constants from a summation?

• Distributive Property

• Summation Property

• Associative Property

• Commutative Property

Tags

CCSS.7.EE.A.1

What is the value of the expression 25 times the summation of a sub i plus 19 times the summation of b sub i?

• 573

• 133

• 27

• 100

Tags

CCSS.7.EE.A.1