Farmer's Motion and Displacement Concepts

The video tutorial explains how a farmer moves along the boundary of a square field, completing one round in 40 seconds. It calculates the speed of the farmer as 1 meter per second and explores how to find the magnitude of displacement after 2 minutes and 20 seconds using the Pythagorean theorem. The tutorial concludes with a call to subscribe for more educational content.

What is the shape of the field along which the farmer moves?

• Triangle

• Rectangle

• Square

• Circle

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CCSS.4.MD.A.2

How long does it take for the farmer to complete one round of the field?

• 50 seconds

• 40 seconds

• 30 seconds

• 20 seconds

What is the speed of the farmer as he moves along the boundary?

• 1.5 meters per second

• 0.5 meters per second

• 1 meter per second

• 2 meters per second

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CCSS.6.RP.A.3B

What is the formula for calculating speed?

• Speed = Distance / Time

• Speed = Distance + Time

• Speed = Distance x Time

• Speed = Time / Distance

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CCSS.HSN.VM.A.3

What do you need to know to calculate the displacement of the farmer?

• Time taken

• Total distance traveled

• Speed of the farmer

• Initial and final positions

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CCSS.4.MD.A.1

CCSS.5.MD.A.1

How much time in seconds does the farmer take to travel in 2 minutes and 20 seconds?

• 140 seconds

• 130 seconds

• 120 seconds

• 150 seconds

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CCSS.4.MD.A.2

What is the total distance traveled by the farmer in 2 minutes and 20 seconds?

• 120 meters

• 150 meters

• 130 meters

• 140 meters

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CCSS.7.NS.A.1A

What is the final position of the farmer after traveling 140 meters?

• At the starting point

• 10 meters from the start

• 20 meters from the start

• 30 meters from the start

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CCSS.8.G.B.8

Which theorem is used to calculate the displacement of the farmer?

• Fermat's theorem

• Euclid's theorem

• Thales' theorem

• Pythagorean theorem

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CCSS.HSN.VM.A.3

What is the magnitude of the farmer's displacement after 2 minutes and 20 seconds?

• 20 meters

• 10√2 meters

• 10 meters

• 20√2 meters

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CCSS.HSN.VM.A.3