What is the result of combining like terms in the polynomial addition process?

Exploring Polynomial Operations: Addition, Subtraction, and Multiplication

Interactive Video
•
Mathematics
•
8th - 12th Grade
•
Hard

Emma Peterson
FREE Resource
10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
You multiply the coefficients of like terms.
You only combine terms with the same variable and degree.
You subtract the coefficients of like terms.
You combine terms of different degrees.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is it important to distribute the subtraction sign when subtracting polynomials?
It ensures you add the coefficients correctly.
It changes all the signs of the terms in the second polynomial.
It has no effect on the outcome.
It simplifies the polynomial to its lowest degree.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does the double distribute method involve?
Distributing each term of one polynomial to all terms of the other polynomial.
Distributing the first term of one polynomial to all terms of the other polynomial.
Distributing each term of one polynomial to only one term of the other polynomial.
Multiplying the leading coefficients only.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the correct expansion of (x + 3)^2?
2x^2 + 6x
x^2 + 6x + 9
x^2 + 9
x^2 + 3x
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why can't you distribute exponents across terms inside parentheses?
Because it violates the order of operations.
Because it results in a lower degree polynomial than expected.
Because it doesn't account for the middle term in binomial expansions.
Because exponents only apply to the term immediately before them.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does the box method help with when multiplying polynomials?
Changing the signs of the coefficients
Organizing terms for easier combination
Eliminating like terms
Reducing the degree of the polynomial
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What mistake do students often make with (x + 3)^2?
Forgetting to square the 3
Expanding it to x^2 + 6x + 9 correctly
Distributing the x across the 3 before squaring
Thinking it equals x^2 + 9
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