Factoring Special Cases of Binomials and Trinomials

Factoring Special Cases of Binomials and Trinomials

Assessment

Interactive Video

Mathematics

8th - 12th Grade

Practice Problem

Hard

CCSS
HSA.APR.C.4

Standards-aligned

Created by

Jackson Turner

FREE Resource

Standards-aligned

CCSS.HSA.APR.C.4
This video tutorial covers special cases of factoring, including the difference of perfect squares, perfect square trinomials, sum of cubes, and difference of cubes. It provides formulas and examples for each case, helping viewers understand how to apply these techniques to factor various algebraic expressions.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for factoring a difference of perfect squares?

A^2 + B^2 = A^2 + 2AB + B^2

A^2 - B^2 = A^2 - 2AB + B^2

A^2 + B^2 = (A + B)^2

A^2 - B^2 = (A + B)(A - B)

Tags

CCSS.HSA.APR.C.4

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you factor a perfect square trinomial?

A^2 + 2AB - B^2 = (A + B)(A - B)

A^2 + B^2 = (A + B)(A - B)

A^2 - 2AB + B^2 = (A - B)^2

A^2 + 2AB + B^2 = (A + B)^2

Tags

CCSS.HSA.APR.C.4

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the factored form of x^2 - 16?

x^2 - 16 = (x + 4)(x - 4)

x^2 - 16 = (x + 16)(x - 16)

x^2 - 16 = x^2 - 8x + 16

x^2 - 16 = (x - 4)^2

Tags

CCSS.HSA.APR.C.4

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the factored form of x^2 - 49?

x^2 - 49 = (x + 7)(x - 7)

x^2 - 49 = (x - 7)^2

x^2 - 49 = (x + 49)(x - 1)

x^2 - 49 = x^2 - 14x + 49

Tags

CCSS.HSA.APR.C.4

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the expression x^2 + 10x + 25 factored?

x^2 + 10x + 25 = (x + 10)(x + 2.5)

x^2 + 10x + 25 = (x + 25)(x + 1)

x^2 + 10x + 25 = (x + 5)^2

x^2 + 10x + 25 = x^2 + 5x + 25

Tags

CCSS.HSA.APR.C.4

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the factored form of 9a^2 + 24a + 16?

9a^2 + 24a + 16 = 9a^2 + 12a + 16

9a^2 + 24a + 16 = (3a - 4)^2

9a^2 + 24a + 16 = (9a + 16)(a + 1)

9a^2 + 24a + 16 = (3a + 4)^2

Tags

CCSS.HSA.APR.C.4

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you factor the sum of perfect cubes?

A^3 + B^3 = (A - B)(A^2 + AB + B^2)

A^3 + B^3 = (A + B)^3

A^3 + B^3 = A^3 + 3A^2B + 3AB^2 + B^3

A^3 + B^3 = (A + B)(A^2 - AB + B^2)

Tags

CCSS.HSA.APR.C.4

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