Balancing Chemical Equations

The video tutorial explains how to balance the decomposition equation of aluminum hydroxide (Al(OH)3) into aluminum oxide (Al2O3) and water (H2O). It begins by counting the atoms on each side of the equation, identifying the need to balance odd numbers by adjusting coefficients. The tutorial demonstrates placing a coefficient of 2 in front of Al(OH)3 to make the numbers even, and then adjusting the coefficients of H2O to balance the hydrogens and oxygens. The video concludes with a balanced equation and emphasizes the importance of making odd numbers even to achieve balance.

What is the initial chemical equation given in the video?

• Al(OH)3 + H2O → Al2O3

• Al2O3 + H2O → Al(OH)3

• Al(OH)3 → Al2O3 + H2O

• Al2O3 → Al(OH)3 + H2O

How many oxygen atoms are there in one molecule of aluminum hydroxide (Al(OH)3)?

• 1

• 2

• 3

• 4

On the product side, how many total oxygen atoms are there?

• 5

• 4

• 3

• 2

What is the purpose of placing a coefficient of 2 in front of Al(OH)3?

• To balance the hydrogen atoms

• To balance the aluminum atoms

• To balance the oxygen atoms

• To make the number of atoms even

After placing a coefficient of 2 in front of Al(OH)3, how many aluminum atoms are there on the reactant side?

• 2

• 4

• 1

• 3

How many hydrogen atoms are there on the reactant side after placing a coefficient of 2 in front of Al(OH)3?

• 3

• 6

• 5

• 4

What coefficient is placed in front of H2O to balance the hydrogen atoms?

• 2

• 1

• 4

• 3

How many total oxygen atoms are there on the product side after balancing?

• 6

• 7

• 5

• 4

What was the trick used to balance the equation?

• Removing some Al2O3

• Adding more H2O

• Multiplying Al(OH)3 by a coefficient of 2

• Multiplying Al(OH)3 by a coefficient of 3

Who is the narrator of the video?

• Dr. C

• Dr. D

• Dr. B

• Dr. A