Solving One-Step Equations: Adding and Subtracting Techniques

This video tutorial covers solving one-step algebraic equations using addition and subtraction. It begins with an introduction to the concept of one-step equations and the importance of inverse operations. The tutorial then demonstrates how to evaluate expressions on both sides of an equation to check for equality. It provides step-by-step examples of solving equations by adding or subtracting to isolate the variable. The video also addresses more complex problems involving fractions and concludes with solving word problems using these techniques.

What is the main goal when solving one-step equations?

• To get the variable on one side by itself

• To add more variables

• To divide both sides by the same number

• To multiply both sides by the same number

Tags

CCSS.6.EE.B.7

What is the inverse operation of subtraction?

• Multiplication

• Division

• Addition

• Subtraction

Tags

CCSS.2.NBT.B.5

If H = 12, does H - 14 equal 2?

• No, because 12 - 14 is 0

• Yes, because 12 - 14 is -2

• No, because 12 - 14 is -2

• Yes, because 12 - 14 is 2

Tags

CCSS.6.EE.B.5

If J = -7, does -11 equal J - 4?

• Yes, because -7 - 4 is -11

• Yes, because -7 - 4 is 3

• No, because -7 - 4 is 3

• No, because -7 - 4 is -3

Tags

CCSS.6.EE.B.5

What is the solution to the equation x - 5 = 17?

• x = 17

• x = 22

• x = 12

• x = 5

Tags

CCSS.6.EE.B.7

What is the solution to the equation p + 3 = 37?

• p = 3

• p = 40

• p = 34

• p = 37

Tags

CCSS.6.EE.B.7

What is the solution to the equation 14 = y + 8?

• y = 22

• y = -6

• y = 6

• y = -22

Tags

CCSS.6.EE.B.7

What is the solution to the equation d + 4.5 = 3.16?

• d = -1.34

• d = -7.66

• d = 1.34

• d = 7.66

Tags

CCSS.6.EE.B.7

If Jagdish scored 87 on his second test, which was 13 points higher than his first test, what was his first test score?

• 100

• 60

• 87

• 74

Tags

CCSS.6.EE.B.7

What is the best way to verify your solution to an equation?

• By using a calculator

• By checking the solution in the original equation

• By guessing

• By asking a friend

Tags

CCSS.8.EE.C.7B