Exploring Slopes of Parallel and Perpendicular Lines

What is the relationship between the slopes of two parallel lines?

• Their slopes are equal.

• Their slopes are opposite reciprocals.

• Their slopes are both zero.

• Their slopes are undefined.

If the slope of line 1 is -3 and the slope of line 2 is -7/2, are the lines parallel?

• No, because their slopes are not equal.

• Yes, because their slopes are equal.

• Yes, because their slopes are opposite reciprocals.

• No, because their slopes are both negative.

Given the points A(13, -6) and B(-12, 36) on line 3, and points C(36, 67) and D(67, -1) on line 4, are lines 3 and 4 parallel?

• No, because their slopes are both positive.

• Yes, because their slopes are opposite reciprocals.

• Yes, because their slopes are equal.

• No, because their slopes are not equal.

What is the equation of a line parallel to y = -3x - 5 that passes through the point (-1, 8)?

• y + 8 = 3(x - 1)

• y - 8 = 3(x + 1)

• y + 8 = -3(x - 1)

• y - 8 = -3(x + 1)

What is the slope of a line perpendicular to a line with a slope of 1/5?

• -1/5

• 5

• -5

• 1/5

If the slope of line 1 is -3/2, what must be the slope of line 2 for the lines to be perpendicular?

• 2/3

• 3/2

• -2/3

• -3/2

Given the points A(27, 31) and B(-2, 6) on line 3, and points C(87, -8) and D(1, 10) on line 4, are lines 3 and 4 perpendicular?

• No, because their slopes are not opposite reciprocals.

• Yes, because their slopes are opposite reciprocals.

• Yes, because their slopes are equal.

• No, because their slopes are both negative.

What is the equation of a line perpendicular to y = 1/5x + 2 that passes through the point (15, 4)?

• y - 4 = -5(x + 15)

• y + 4 = 5(x - 15)

• y - 4 = 5(x + 15)

• y + 4 = -5(x - 15)

A player runs along a path perpendicular to the path of a baseball with a slope of 1/3. What is the slope of the player's path?

• 3

• 1/3

• -3

• -1/3

What is the equation of a line parallel to the path of a baseball with a slope of 1/3 that passes through the point (90, 40)?

• y - 40 = 1/3(x - 90)

• y + 40 = 1/3(x + 90)

• y - 40 = -1/3(x - 90)

• y + 40 = -1/3(x + 90)