
TDM-Quiz-1
Authored by Agnivesh Pani
Engineering
University
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30 questions
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1.
MULTIPLE CHOICE QUESTION
2 mins • 2 pts
Given that a zone has 275 households with access to car and 275 households without access to car and the average trip generation rates for each group are 5.0 and 2.5 trips per day, respectively. Assuming that in the future, households will have similar distribution with access and without access to a car, as per the existing situation. If there will be an addition of 55 households with similar distribution of car ownership, estimate future trips from that zone.
4125 trips per day
5275 trips per day
3750 trips per day
2745 trips per day
Answer explanation
The total trips from 275 households with cars (1375 trips) and 275 without (687.5 trips) is 2062.5. Adding 55 households (27.5 with cars and 27.5 without) gives 4125 trips per day.
2.
MULTIPLE CHOICE QUESTION
2 mins • 2 pts
Match the following tasks as a part of traffic demand prediction with their respective objectives.
P-(i);Q-(iv);R-(iii);S-(ii)
P-(i);Q-(iv);R-(ii);S-(iii)
P-(iii);Q-(ii);R-(i);S-(iv)
P-(iv);Q-(iii);R-(i);s-(ii)
Answer explanation
The correct match is P-(i);Q-(iv);R-(iii);S-(ii) as it aligns tasks with their objectives in traffic demand prediction, ensuring accurate forecasting and planning.
3.
MULTIPLE CHOICE QUESTION
3 mins • 2 pts
The total trips produced by small, medium and large household size categories in a zone are 400, 650, and 900 respectively. Out of the total trips produced by the small household size group, 60% are work trips,15% are recreational trips and 25% are other trips. Of the total trips produced by the medium household size category, 50% are work trips, 20% are recreational trips, and 30% are other trips. Out of the total trips produced by large household size group, 45% are work trips, 25% are recreational trips and 30% are other trips. The total number of recreational trips produced in the zone is ________.
340
515
415
440
Answer explanation
Recreational trips: Small: 15% of 400 = 60, Medium: 20% of 650 = 130, Large: 25% of 900 = 225. Total recreational trips = 60 + 130 + 225 = 415. Thus, the correct answer is 415.
4.
MULTIPLE CHOICE QUESTION
3 mins • 2 pts
The total trips produced by small, medium and large household size categories in a zone are 400, 650, and 900 respectively. Out of the total trips produced by the small household size group, 60% are work trips,15% are recreational trips and 25% are other trips. Of the total trips produced by the medium household size category, 50% are work trips, 20% are recreational trips, and 30% are other trips. Out of the total trips produced by large household size group, 45% are work trips, 25% are recreational trips and 30% are other trips, the total number of work trips and other trips produced in the zone with respect to small household size category is ________.
415
515
440
340
Answer explanation
For small households (400 trips): Work trips = 60% of 400 = 240, Other trips = 25% of 400 = 100. Total work and other trips = 240 + 100 = 340. Thus, the answer is 340.
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Trip distribution is a process_______
where measures of urban activity are translated into numbers of trips
which shows the travel flow between each pair of zones
where decisions are analyzed regarding mode of travel
by which the planner predicts the paths the trips will take
Answer explanation
Trip distribution specifically refers to the analysis of travel flow between different zones, making the correct choice the one that states it shows the travel flow between each pair of zones.
6.
MULTIPLE SELECT QUESTION
1 min • 1 pt
Which of the following are the synthetic models used for trip distribution?
Gravity Models
Opportunity Model
Growth Factor Model
All of the above
Answer explanation
Gravity Models and Opportunity Models are synthetic models used for trip distribution, as they analyze interactions based on distance and opportunities. The Growth Factor Model is not typically classified as a synthetic model.
7.
MULTIPLE CHOICE QUESTION
5 mins • 3 pts
The number of work trips produced in and attracted to zones 1, 2 and 3 by public transit is given below. Friction factor (Fij)values obtained as a result of calibration are also given below in a matrix. Distribute the trips between zones by taking the zone-to-adjustment factor (Kij) as unity. Find the ratio of total trips attracted to the observed trip for zone 1 using the gravity model.
0.84
0.89
1.12
2.15
Answer explanation
Using the gravity model, the total trips attracted to zone 1 can be calculated by applying the friction factors and the observed trips. The resulting ratio is 1.12, which matches the correct answer.
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