Math 1 Module Six Study Guide

Solve the system using elimination.

3x + 3y = –9

3x – 3y = 21

• (2, –5)

• (–5, 2)

• (6, –4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system using elimination.

5x + 2y = –19

2x – 2y = –16

• (1, 7)

• (–4, 0.5)

• (–5, 3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system using elimination.

2x + 3y = 1

2x – 3y = –17

• (–4, 3)

• (3, 2)

• (3, –4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system using elimination.

2x + 3y = –5

5x – 3y = 40

• (5, –5)

• (–5, 5)

• (5, 5)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system using elimination. x + 4y = 4 x – 4y = –12

• (–4, 2)

• (2, –4)

• (–4, 1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = x + 4 y - 4 = x

• intersecting

• parallel

• same line

Tags

CCSS.8.EE.C.8B

y = 2x - 3

y = -x + 3

• intersecting

• parallel

• same line

Tags

CCSS.8.EE.C.8B

Which of the answers is the solution to the system of equations:

• The solution to the system is (2, 4).

• The solution to the system is (−2, −4).

• The solution to the system is (−2, 4).

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve this system by substitution:

-2x + 3y = 4

y = 0

• (0,-2)

• (-2,0)

• (2,3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve this system by substitution:

x + y = 10

y = 2x + 1

• (7,3)

• (2,1)

• (3,7)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6