Mastery View Predictive Assessments Grade 5 Math 2024-2025 Final

What is 4,176 × 32?

• A. 133,632

• B. 133,600

• C. 131,422

• D. 131,412

Tags

CCSS.5.NBT.B.5

What is the value of the digit 9 when 3.9 is multiplied by 10³?

• A. 9

• B. 90

• C. 900

• D. 9,000

Tags

CCSS.5.NBT.A.2

A large pot for cooking has a capacity of 12 liters. What is the capacity of the large pot, in milliliters?

• 1.2 milliliters

• 120 milliliters

• 1,200 milliliters

• 12,000 milliliters

Tags

CCSS.4.MD.A.1

CCSS.5.MD.A.1

Which equation is true?

• 7,488 ÷ 24 = 332

• 6,405 ÷ 21 = 304

• 5,643 ÷ 19 = 297

• 4,495 ÷ 31 = 135

Tags

CCSS.5.NBT.B.6

CCSS.6.NS.B.2

Consider the two patterns. - Pattern G: Start with 3, multiply by 2. - Pattern H: Start with 8, add 2. If Pattern G represents the x-coordinate, and Pattern H represents the y-coordinate in an ordered pair, which table correctly represents the first four ordered pairs?

• Pattern G (x) 3, 11, 19, 27; Pattern H (y) 2, 4, 6, 8

• Pattern G (x) 3, 6, 12, 24; Pattern H (y) 8, 10, 12, 14

• Pattern G (x) 3, 6, 9, 12; Pattern H (y) 8, 10, 12, 14

• Pattern G (x) 3, 5, 7, 9; Pattern H (y) 2, 4, 6, 8

Tags

CCSS.5.OA.B.3

Tags

CCSS.5.NF.A.1

CCSS.5.NF.A.2

A gardener weighs a lemon and an orange. The total weight of the lemon and the orange is 0.51 pound. If the lemon weighs 0.13 pound, how much does the orange weigh?

• 0.37 pound

• 0.38 pound

• 0.64 pound

• 0.65 pound

Tags

CCSS.6.NS.B.3

A teacher gives a group of students a card with an expression written, as shown. 2 × [(48 + 16) ÷ 8] The teacher asks each student in the group to write the value of the expression. The table shows the responses. Student 1: 14 Student 2: 100 Student 3: 8 Student 4: 16 Which student writes the correct value of the expression?

• Student 1

• Student 2

• Student 3

• Student 4

Tags

CCSS.6.EE.A.1

What is the quotient when 5.4 is divided by 9?

• 0.06

• 0.6

• 6

• 60

Tags

CCSS.5.NBT.B.7

Which equation is correct?

• 59/100 - 2/5 = 57/100

• 59/100 - 2/5 = 19/100

• 59/100 - 2/10 = 57/100

• 59/100 - 2/10 = 29/100

Tags

CCSS.5.NF.A.1

CCSS.5.NF.A.2