Electric Potential and Capacitance

Define electric potential energy and provide its formula.

• U = m * g * h

• U = q * E * d

• U = k * (q1 * q2) / r

• U = 1/2 * k * x^2

A capacitor of capacitance 5 µF is charged to a potential difference of 10 V. Calculate the electric potential energy stored in the capacitor.

• 0.005 J

• 0.01 J

• 0.00025 J

• 0.0005 J

Explain the concept of capacitance in series and derive the formula for total capacitance.

• Ct = C1 + C2 + ... + Cn

• Ct = C1 * C2 * ... * Cn

• Ct = 1 / (1/C1 + 1/C2 + ... + 1/Cn)

• Ct = C1 - C2 - ... - Cn

Two capacitors, 4 µF and 6 µF, are connected in series. Calculate the total capacitance of the combination.

• 1.5 µF

• 2.4 µF

• 3.0 µF

• 5.0 µF

Describe capacitance in parallel and derive the formula for total capacitance.

• C_total = 1/(1/C1 + 1/C2 + ... + 1/Cn)

• C_total = C1 * C2 * ... * Cn

• C_total = C1 + C2 + ... + Cn

• C_total = C1 - C2 - ... - Cn

Three capacitors of capacitance 2 µF, 3 µF, and 5 µF are connected in parallel. Find the total capacitance.

• 7 µF

• 8 µF

• 10 µF

• 6 µF

What is the energy stored in a capacitor? Provide the formula and explain each term.

• E = C V

• E = 1/2 C V

• The energy stored in a capacitor is given by the formula: E = 1/2 C V^2.

• E = C V^3

A capacitor of 10 µF is charged to 20 V. Calculate the energy stored in the capacitor.

• 1 mJ

• 2 mJ

• 5 mJ

• 10 mJ

What effect does a dielectric have on the capacitance of a capacitor?

• A dielectric has no effect on the capacitance of a capacitor.

• A dielectric decreases the capacitance of a capacitor.

• A dielectric increases the capacitance of a capacitor.

• A dielectric makes the capacitor less efficient.

A capacitor with a capacitance of 8 µF is filled with a dielectric material of dielectric constant 4. Calculate the new capacitance.

• 40 µF

• 16 µF

• 24 µF

• 32 µF