Algebra 1 - Unit 3 Review

Solve
x² + 2x - 24 = 0

• x = -6, x = 4
• x = 6, x = -4
• x = 12, x = -2
• x = 8, x = -3

Tags

CCSS.HSA-REI.B.4B

Solve:

X² - 3 =6X + 10

• X = $\frac{6\pm\sqrt{88}}{2}$

• x= $3\ \pm\sqrt{22}$

• X = $-3\pm\sqrt{22}$

• No Solution

Tags

CCSS.HSA-REI.B.4B

• -2

• 2

• -4

• 4

Tags

CCSS.HSA-REI.B.4B

• -8.5

• 8.5

• 1

• -1

Tags

CCSS.HSA-REI.B.4B

• -74 and 88

• -2 and 16

• -88 and 74

• -16 and 2

Tags

CCSS.HSA-REI.B.4B

• x = 3 and x = 11

• x = -1 and x = 15

Tags

CCSS.HSA-REI.B.4B

Solve the following quadratics equation by completing the square...

x² + 6x - 3 = 0

Tags

CCSS.HSA-REI.B.4B

We found the discriminant of y = x² + 4x + 4 to be 0. How many real solutions does the function have?

• One

• Two

• None

Tags

CCSS.HSA-REI.B.4B

What is the discriminant of -2x² − x − 1 = 0?

• 76

• -7

• 9

• none of these

Tags

CCSS.HSA-REI.B.4B

Determine the values of

a, b, and c for

the quadratic equation:

4x² – 8x = 3

• a = 4, b = -8, c = 3

• a = 4, b =-8, c =-3

• a = 4, b = 8, c = 3

• a = 4, b = 8, c = -3