Quiz about Participación 6. Ecuación canónica u ordinaria de la elipse

Question 1

De la elipse $$\frac{x^2}{8}+\frac{y^2}{6}=1$$ , la distancia que separa al centro de alguno de sus focos es:

Accepted Answer

$$\sqrt[]{2}$$ u

Answer

$$2\sqrt[]{2}$$ u

Answer

$$\sqrt[]{28}$$ u

Answer

$$\sqrt[]{14}$$ u

Question 2

Longitud de los tres semiejes de la elipse siguiente:

$$\frac{\left(x-5\right)^2}{2}+\frac{\left(y-4\right)^2}{4}=1$$

Accepted Answer

$$2,\ \sqrt[]{2}$$ y $$\sqrt[]{2}$$

Answer

$$4,\ 2$$ y $$\sqrt[]{2}$$

Answer

$$2,\ 1\ y\ \sqrt[]{2}$$

Answer

$$2,\ \sqrt[]{2}$$ y $$\sqrt[]{6}$$

Question 3

Determina las coordenadas de los extremos de la elipse representada como:

$$\frac{\left(x-4\right)^2}{49}+\frac{\left(y+1\right)^2}{25}=1$$

Accepted Answer

$$E\left(4,-6\right)$$ $$E\left(4,4\right)$$

Answer

$$E\left(4,-4\right)$$

$$E\left(4,6\right)$$

Answer

$$E\left(-4,-1\right)$$

$$E\left(12,-1\right)$$

Answer

$$E\left(4,-5\right)$$ $$E\left(4,5\right)$$

Question 4

Longitud de los lados rectos de la elipse representada como sigue:

$$\frac{\left(x-1\right)^2}{9}+\frac{\left(y+7\right)^2}{8}=1$$

Accepted Answer

$$LR=\frac{16}{3}$$ u

Answer

$$LR=\frac{128}{9}$$ u

Answer

$$LR=\frac{16}{9}$$ u

Answer

$$LR=\frac{128}{3}$$ u

Question 5

Determina la excentricidad de esta elipse:

$$\frac{\left(x-5\right)^2}{144}+\frac{\left(y-1\right)^2}{225}=1$$

Accepted Answer

$$e=\frac{3}{5}$$

Answer

$$e=\frac{15}{9}$$

Answer

$$e=\frac{9}{12}$$

Answer

$$e=\frac{3}{4}$$

Question 6

Encuentra la excentricidad de la elipse representada por:

$$\frac{\left(x+4\right)^2}{49}+\frac{\left(y-2\right)^2}{24}=1$$

Accepted Answer

$$e=71.4\%$$

Answer

Answer

$$e=48.9\%$$

Answer

$$e=17.4\%$$

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