TECHTRIX2025 BUGHUNT SET6

What is the error in the following C code? #include int main() { int arr[3] = {1, 2, 3}; printf("%d", arr[3]); return 0; } Explanation: The array has indices from 0 to 2. Accessing arr[3] is out of bounds.

• printf("%d", arr[2]);

• printf("%d", arr[3]); (No error)

• printf("%d", arr[0]);

• printf("%d", arr[4]);

What should be the correct condition in this code? #include int main() { int x = 5; if (x = 10) { printf("Hello"); } return 0; } Explanation: x = 10 is an assignment, not a comparison. Use == for comparison.

• if (x = 10)

• if (x == 10)

• if x == 10;

• if (x := 10)

Identify the correct line to fix the segmentation fault. #include int main() { int *ptr; *ptr = 10; printf("%d", *ptr); return 0; } Explanation: The pointer is uninitialized, leading to undefined behavior. Assign a valid memory address.

• int ptr = 10;

• int *ptr = NULL;

• int x = 10; int *ptr = &x;

• int *ptr = 10;

Find the correct way to swap two numbers using pointers. #include void swap(int *a, int *b) { int temp = *a; *a = *b; *b = temp; } int main() { int x = 5, y = 10; swap(x, y); printf("%d %d", x, y); return 0; } Explanation: The function expects pointers, so we must pass the addresses of x and y.

• swap(x, y);

• swap(&x, &y);

• swap(*x, *y);

• swap(x, *y);

Identify the correct loop termination condition. #include int main() { int i = 0; while (i = 10) { printf("%d", i); i++; } return 0; } Explanation: i = 10 is an assignment, not a condition. The loop should run until i < 10.

• while (i = 10)

• while (i == 10)

• while (i < 10)

• while (i <= 10)

What will be the output? #include int main() { printf("%d", printf("RCCIIT")); return 0; } Explanation: printf("RCCIIT") prints "RCCIIT" and returns 6, which is printed by the second printf.

• RCCIIT

• 6

• RCCIIT6

• Error

What is the output? #include int main() { int x = 6, y = 1; if (x & y) { printf("Yes"); } else { printf("No"); } return 0; } Explanation: 6 & 1 results in 0 (bitwise AND), so the else block executes.

• Yes

• No

• 0

• Error

What is the output of this expression? #include int main() { int a = 5, b = 2; printf("%d", a / b * b); return 0; } Explanation: Integer division 5/2 = 2, then 2*2 = 2.

• 5

• 4

• 2

• 0

Identify the correct statement. #include int main() { int x = 5; int y = x++ + ++x; printf("%d", y); return 0; } Explanation: x++ and ++x are both modifying x without sequence points, leading to undefined behavior.

• y = 10

• y = 12

• y = 11

• Undefined behavior

What will be the value of y? #include int main() { int x = 3; int y = (x << 2) + (x >> 1); printf("%d", y); return 0; } Explanation: • x << 2 shifts left → 3 * 4 = 12 • x >> 1 shifts right → 3 / 2 = 1 • 12 + 1 = 14

• 12

• 10

• 14

• 8