EN 2-3

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EN 2-3

EN 2-3

Assessment

Quiz

Engineering

University

Practice Problem

Medium

Created by

Christian Mina

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35 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

For a beta of 120, compute the collector current of the given circuit

2.26 mA

2.25 mA

2.24 mA

2.23 mA

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Given VCC = 10 V, RC = 4.7 kΩ, RB = 250Ω, RE = 1.2 kΩ and β = 90 for the circuit shown, find:
(a) IB
(b) IC and
(c) VCE

IB = -11.91 uA, IC = 1.07 mA, VCE = 3.687 V

iB = -11.91 uA, IC = 1.07 mA, VCE = 3.688 V

B = -11.91 uA, IC = 1.07 mA, VCE = 3.689 V

B = -11.91 uA, IC = 1.07 mA, VCE = 3.690 V

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Calculate the value of V6 and I5 for the circuit shown. Assume that β has a very large value.

V6 = -4.475 V and I5 = 0.965 mA

V6 = -4.475 V and I5 = 0.966 mA

V6 = -4.475 V and I5 = 0.967 mA

V6 = -4.475 V and I5 = 0.968 mA

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Find V_2 if it assumes that the given circuit has a very large beta.

V_2 = -0.6 V

V_2 = -0.7 V

V_2 = -0.8 V

V_2 = -0.9 V

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Find the value of VE, β, α, and VC for the given circuit if a measurement indicates that base voltage is -1.5V.4

VE = -2.2 V, β = 3.53, α = 0.779, and VC = 3.7 V

VE = -2.2 V, β = 3.53, α = 0.779, and VC = 3.8 V

VE = -2.2 V, β = 3.53, α = 0.779, and VC = 3.9 V

VE = -2.2 V, β = 3.53, α = 0.779, and VC = 4.0 V

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

For the JFET in the figure shown, VGS(off) = - 4V and IDSS = 12 mA, Determine the minimum value of VDD required to put the device in the constant-current region of operation.

VDD(min) = 10.71 V

VDD(min) = 10.72 V

VDD(min) = 10.73 V

VDD(min) = 10.74 V

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The data sheet of a JFET gives the following information:
IDSS = 3 mA
VGS(off) = - 6V
gm (max) = 5,000 uS.

Determine the transconductance for VGS = -4V and find drain current ID at this point.

gm = 1.67 mS and ID = 0.33 mA

gm = 1.68 mS and ID = 0.33 mA

gm = 1.69 mS and ID = 0.33 mA

gm = 1.70 mS and ID = 0.33 mA

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