Unit 8 Lesson 2 Solving Quadratics

• A
• B
• C
• D

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form
• Write down: a=1, b=6, c=-13
• Make it equal 0 by subtracting 3 on each side
• Type it all in a calculator.

Solve: b² = -35 + 12b RE-ARRANGE AND FACTOR

• b = 5 and 7

• b = -5 and -7

• b = -5 and 7

• b = 5 and -7

Solve by factoring: x² = 7x + 18

• -7 and -18

• 9 and 2

• 9 and -2

• 2 and 7

Suzie solves the equation below:

x² + 4x - 12 = 2

(x - 2)(x + 6) = 2,

by setting x - 2 = 0 and x + 6 = 0

Her solutions are x = 2 and x = -6.

Is Suzie correct? Why or why not?

• Yes, she factored correctly and then used the multiplication property of zero

• Yes, she factored correctly and then square rooted both sides

• No, the equation must be in standard form set equal to zero before factoring

• No, she didn't factor correctly so the rest of her work is wrong.

Find the solutions.

x² + 4x= 12

• x = 2 and -2

• x = -6 and 2

• x = 6 and -2

• x = 1 and -1

• (x-3)(5x+ 2)

• (x+3)(5x+ 2)

• (x-3)(x +2)

• (x+3)(x+2)

Solve by factoring: x² = 9x - 20

• x = -4 and x = -5

• x = 20 and x = -9

• x = 4 and x = 5

• x = -4 and x = 5

• 3

• 8

• -9

• -3