Factoring Polynomials and Finding Roots in Real-World Scenarios

Factoring Polynomials and Finding Roots in Real-World Scenarios

9th Grade

10 Qs

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Factoring Polynomials and Finding Roots in Real-World Scenarios

Factoring Polynomials and Finding Roots in Real-World Scenarios

Assessment

Quiz

English, Mathematics

9th Grade

Hard

Created by

Anthony Clark

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A gardener is planting a rectangular flower bed. The area of the bed can be represented by the polynomial A(x) = x^2 - 9. What are the dimensions of the flower bed if the width is x - 3?

Width: x - 3, Length: x - 3

Width: x + 3, Length: x - 3

Width: x - 3, Length: x + 3

Width: x + 3, Length: x + 3

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A car's speed can be modeled by the polynomial S(t) = t^2 - 4t. What are the times when the car is stationary?

t = 0, t = 4

t = 1

t = -4

t = 2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A rectangular pool has a length represented by the polynomial L(x) = x^2 - 16. If the width is x - 4, what are the possible dimensions of the pool?

(x^2 - 16, x - 4)

(x^2 - 8, x + 2)

(x^2 - 4, x - 2)

(x^2 + 16, x + 4)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A company produces x^2 - 25 units of a product. If they want to factor this polynomial to find the number of units produced, what are the factors?

(x - 1)(x + 25)

(x - 5)(x - 5)

(x - 10)(x + 10)

(x - 5)(x + 5)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A rectangular garden has an area represented by the polynomial A(x) = x^2 - 1. If one side is x + 1, what is the length of the other side?

x - 1

x + 1

x - 2

x^2 + 1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A box's volume is given by the polynomial V(x) = x^3 - 8. If one dimension is x - 2, what are the possible dimensions of the box?

x + 2

x^3 - 2

x^2 - 4

x - 2, x^2 + 2x + 4 (complex dimensions)

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A farmer has a field with an area represented by the polynomial A(x) = x^2 - 36. If the length is x + 6, what is the width of the field?

x + 12

x + 6

x - 6

x - 12

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