Unit 5 Exam Review: Vertex Form

 $y=-3(x+5)^2-4$  
Convert the equation from vertex form to standard form.

• y = 9x² - 15x + 21

• y = -3x² - 75x - 4

• y = 9x² + 90x + 221

• y = -3x² - 30x - 79

 $y=4(x+2)^2-8$ 

Convert the equation from vertex form to standard form. 

•  $y=4x^2+16x+8$  

•  $y=4x^2+16x+16$  

•  $y=16x^2+64x-8$  

•  $y=16x^2+256x+8$  

Convert f(x) = 3x²+ 6x - 5 to vertex form.

• f(x) = 3(x + 1)² - 8

• f(x) = 3(x - 1) ² - 8

• f(x) = 3(x + 2)² - 8

• f(x) = 3(x - 2)² - 8

If given the equation f(x) = 3(x + 5)² - 4, what is the vertex of the parabola?

• (5, -4)

• (-5, -4)

• (-15, -4)

• (15, -4)

What is the vertex?

• (2, 4)
• (3, -1)
• (0, 8)
• (4, 2)

Convert the equation y= x²-2x-5 into vertex form. 

• y= (x-1)²-6
• y= -(x-1)²-6
• y= (x+1)²-6
• y= -(x+6)²-1

Use the graph to determine the X-intercepts

• (-1,0) and (-3,0)

• (1,0) and (3,0)

• (0,1) and (0,3)

• (0,-1) and (0,-3)

Tags

CCSS.HSF-IF.C.7A

What is the equation for axis of symmetry?

• y=3
• x=3
• x=5
• x=1

Tags

CCSS.HSF-IF.C.7A

What is the range of this function?

• (- ∞,+∞)
• [0, +∞)
• [-2, +∞)
• [2, +∞)

Tags

CCSS.HSF-IF.C.7A

Which parabola would open down?

• f(x)=x²

• f(x)=-x²+3x-6

• f(x) = x²-16

• f(x)=2x²-5x+7

Tags

CCSS.HSF-IF.C.7A