UNIT 7 - CFA - PRACTICE - DAY 2

Add the following polynomials:
(x³-2x²+3)+(2x³+3x²-1)

• 3x³-2x²+3x+2
• 3x³+x²+2
• 3x³-5x²-2
• 3x³-x²+1

Tags

CCSS.HSA.APR.A.1

Subtract the following polynomials:
(3x²-3x+2)-(x²-2x+1)

• 2x²+x+1
• 2x²-5x+3
• 2x²-x+1
• 4x²-5x+3

Tags

CCSS.HSA.APR.A.1

• A

• B

• C

• D

Tags

CCSS.HSA.APR.A.1

• x²+4x+8

• x²+8x+8

• x²+8x+6

• x²+6x+8

The solutions of the quadratic equation 
x²+2x-15=0 are

• x = 3 or x = 5
• x = 5 or x = -3
• x = -5 or x = 3
• x = -3 or x = -5

Tags

CCSS.HSA-REI.B.4B

Solve by factoring.

x² - x - 20 = 0

• x = -5, x = 4

• x = 5, x = -4

• x = 10, x = -2

• x = -10, x = 2

Tags

CCSS.HSA-REI.B.4B

Factor:

p² - 14p

• p(1 - 14)

• 2p(p - 7)

• p²(1-14)

• p(p - 14)

Factor Completely:  3n² - 15n + 18

• (n - 2)(n - 3)
• 3(n + 2)(n + 3)
• (3n - 9)(n - 2)
• 3(n - 3)(n - 2)

Convert x² - 9x + 20 = 0 to factored form and solve.

• (x-10)(x+2); x = -2, 10

• (x+4)(x+5); x = -5, -4

• (x-4)(x-5); x = 4, 5

• Not factorable

Tags

CCSS.HSA-REI.B.4B

Factor x² + 6x + 9 = 0 and solve for x.

• (x+3)(x+3); x = -3

• (x+4)(x+5); x=-4, -5

• (x-3)(x-3); x=3

• Not factorable

Tags

CCSS.HSA-REI.B.4B