Calculating Empirical Formula

A compound consists of 72.2% magnesium(Mg) and 27.8% nitrogen(N) by mass. What is the empirical formula?

• Mg₄N₃

• MgN₂

• Mg₃N₂ 

• MgN

Tags

NGSS.HS-PS1-2

2.40 g of an explosive, J, contains 0.473 g of nitrogen. J also contains 33.8% carbon and 1.41% hydrogen by mass. The remainder of J is oxygen.

What is the empirical formula of J?

• C₄HNO₂

• CH₂N₂O

• C₂HNO₂

• CHNO

Tags

NGSS.HS-PS1-2

NGSS.HS-PS1-7

A 5.00 g sample of a compound consisting of calcium and chlorine contains 1.82 g of calcium and 3.23 g of chlorine. What is the empirical formula

• CaCl₂

• Ca₂Cl₂

• Ca₂Cl₄

• Ca₄Cl₂

Match the following steps for calculating an empirical formula

• Mass to Mole

• Step 3

•  Divide by Small

• Step 1

• Multiply till Whole

• Step 4

• Percent to Mass

• Step 2

Match the following directions for each step in finding an empirical formula

• Divide by the smallest answer from step

• Step 4: Multiply till Whole

• Divide each atom by the molar mass

• Step 2. Mass to Mole

• .5-> x2, .33 -> x3 etc.

• Step 3. Divide by Small

•  Assume the percent is equal to grams

• Step 1. Percent to Mass

What is the empirical formula of a substance with the molecular formula Se₈F₁₂?

• Se₈F₁₂

• Se₂F₃

• Se₄F₃

• SeF

What is the empirical formula if you have 88.80% copper and 11.20% oxygen?

• Cu₃C₈

• Cu₂O

• CuO₄

• Cu₄O₁₀

You are given the following percentages: 40.05% S and 59.95% O. Find the empirical formula for these elements.

• SO

• SO2

• SO3

• SO4

A compound is composed of 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen by mass. What is the empirical formula of the compound?

An unknown compound is found to contain 36.8% nitrogen and 63.2% oxygen by mass. Determine the empirical formula of the compound.