AP Biology Hardy Weinberg

AP Biology Hardy Weinberg

12th Grade

15 Qs

quiz-placeholder

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AP Biology Hardy Weinberg

AP Biology Hardy Weinberg

Assessment

Quiz

Science

12th Grade

Practice Problem

Hard

NGSS
HS-LS4-3, HS-LS4-4, HS-LS4-5

+2

Standards-aligned

Created by

Lisa Thompson

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15 questions

Show all answers

1.

MULTIPLE SELECT QUESTION

1 min • 1 pt

Select ALL of the following that violate the Hardy-Weinberg assumptions and would lead to a change in allele frequencies in a population.

natural selection

large population

no mutations

nonrandom mating

no migration

Tags

NGSS.HS-LS4-4

NGSS.HS-LS4-5

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

There are 3 T alleles and 7 t alleles in a population. Calculate the frequency of the recessive allele.

30%

70%

10%

4%

Tags

NGSS.HS-LS4-3

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

A drastic reduction in the size of a population that can change allele frequencies is called

the bottleneck effect

the founder effect

the gene flow effect

the Thanos effect

Tags

NGSS.HS-LS4-5

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Alleles that improve survival will decrease in frequency in the next generation.

True

False

Tags

NGSS.HS-LS4-2

NGSS.HS-LS4-4

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

An allele combination (BB, Bb, or bb) is called a

phenotype

genotype

mutation

gene flow

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

If the frequency of allele $A$ is 0.8 in a population at Hardy-Weinberg equilibrium, what is the frequency of the genotype $aa$?

0.04

0.16

0.64

0.32

Answer explanation

In Hardy-Weinberg equilibrium, the frequency of genotype $aa$ is given by $q^2$. If the frequency of allele $A$ (p) is 0.8, then $q = 1 - p = 0.2$. Thus, $q^2 = (0.2)^2 = 0.04$. Therefore, the frequency of genotype $aa$ is 0.04.

Tags

NGSS.HS-LS3-3

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

If the frequency of the recessive phenotype is 0.09 in a population at Hardy-Weinberg equilibrium, what is the frequency of the dominant allele?

0.7

0.3

0.81

0.9

Answer explanation

In Hardy-Weinberg equilibrium, the frequency of the recessive phenotype (q^2) is 0.09. Thus, q = √0.09 = 0.3. The frequency of the dominant allele (p) is 1 - q = 1 - 0.3 = 0.7, which is the correct answer.

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