Thermochemical Equations

Is the following exothermic or endothermic?

• Endothermic

• Exothermic

Tags

NGSS.HS-PS1-4

Is the following exothermic or endothermic?

• Endothermic

• Exothermic

Tags

NGSS.HS-PS1-4

What will ΔH be if there is 1 mole of oxygen?

• -500 kJ

• 500 kJ

• -750 kJ

• -4500 kJ

Tags

NGSS.HS-PS1-4

What is ΔH if 2 mol of O₂(g) is reacted in this reaction?

• -570 kJ

• -71.45 kJ

• -1143.2 kJ

• -142.9 kJ

Tags

NGSS.HS-PS1-4

NGSS.HS-PS3-1

NGSS.HS-PS3-4

What mass of P₄ must be reacted to produce 5905 kJ of energy?

• 25.43 g

• 563.0 g

• 2.421 g

• 300.0 g

Tags

NGSS.HS-PS1-4

NGSS.HS-PS3-1

What type of reaction is shown in the reaction pathway?

• endothermic reaction

• exothermic reaction

Tags

NGSS.HS-PS1-4

Consider the following reactions:Fe(s) + 1/2 O2(g) --> FeO(s) H= -272.0 kJ2 Fe(s) + 3/2 O2(g) --> Fe2O3(s) H= -825.5 kJDetermine the delta H for the reaction: 2 FeO(s) + 1/2 O2(g) --> Fe2O3

• -281.5 kJ

• -1097.5 kJ

• -1369.5 kJ

• 281.5 kJ

Tags

NGSS.HS-PS1-4

NGSS.HS-PS3-1

The thermochemical equation for the incomplete combustion of carbon into carbon monoxide is represented as: 2C (s) + O₂(g) --> 2CO(g)

Compute for the H of the reaction if the overall process above can occur in two steps whose thermochemical equations are given below:

(1) C _(s) + O_2(g) --> CO_2(g) H= -392.5 kJ

(2) 2 CO_(g) + O_2(g) --> 2CO_2(g) H= -566.0 kJ

• 172.5 kJ

• 1,353 kJ

• -221.0 kJ

• 959.5 kJ

Tags

NGSS.HS-PS3-1

Determine the H for reaction of this equation: 3C (graphite) + 4 H2(g) --> C3H8(g)

using these intermediates:

(A) C₃H₈ (g) + 5O₂(g) --> 3CO₂ (g) + 4H₂O (l) H= -2219.9 kJ

(B) C(graphite) + O₂(g) --> CO₂ (g) H= -393.5 kJ

(C) H₂ (g) + 1/2 O₂ (g) --> H₂O (l) H= -285.8 kJ

• -683.4 kJ

• -2899.2 kJ

• -1324.7 kJ

• -104.0 kJ

Tags

NGSS.HS-PS1-4

NGSS.HS-PS3-1

The enthalpy change for the reaction, ∆H_r , is equal to 

• ∆H₁ + ∆H₂

• ∆H₁ - ∆H₂

• -∆H₁ - ∆H₂

• -∆H₁ + ∆H₂

Tags

NGSS.HS-PS1-4