Equilibrium Constant

Equilibrium Constant

11th - 12th Grade

10 Qs

quiz-placeholder

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Equilibrium Constant

Equilibrium Constant

Assessment

Quiz

Chemistry

11th - 12th Grade

Hard

NGSS
HS-PS1-6, HS-PS1-7, HS-PS1-5

Standards-aligned

Created by

Charles Martinez

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

An equilibrium constant with a value K > 1 means:
a. there are more reactants than products at equilibrium
b. there are more products than reactants at equilibrium
c. there are the same amount of products and reactants at equilibrium
d. the reaction is not at equilibrium

Tags

NGSS.HS-PS1-6

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Equal amounts of reactants are poured into a suitable container. Given sufficient time, the reactants may be converted almost entirely to products if:
a. K is less than 1
b. K is greater than 1
c. K is equal to 1
d. K is equal to 0

Tags

NGSS.HS-PS1-6

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

The equilibrium constant for the reaction H2 (g) + I2 (g) ↔ 2 HI (g) would be
a. K = [HI]2/[H2][I2]
b. K = [H2][I2]/[HI]2
c. K = 2[HI]/[H2][I2]
d. K = [H2][I2]/2[HI]

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

The equilibrium constant for the reaction 2 SO2 (g) + O2 (g) ↔ 2 SO3 (g) would be
a. K = 2[SO3]/2[SO2][O2]
b. K = 2[SO2][O2]/[SO3]
c. K = [SO3]2/[SO2]2[O2]
d. K = [SO2]2[O2]/[SO3]2

Tags

NGSS.HS-PS1-7

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

The equilibrium constant for the reaction Ca(HCO3)2 (s) ↔ CaO (s) + 2 CO2 (g) + H2O (g) would be
a. K = [CaO][CO2]2[H2O]/[Ca(HCO3)2]
b. K = [Ca(HCO3)2]/[CaO][CO2]2[H2O]
c. K = [CO2]2
d. K = [CO2]2[H2O]

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

The equilibrium constant for the reaction SnO2 (s) + 2 H2 (g) ↔ Sn (s) + 2 H2O (g) would be
a. K = [H2O]2/[H2]2
b. K = [Sn][H2O]2/[SnO][H2]2
c. K = [SnO][H2]2/[Sn][H2O]2
d. K = [H2]2/[H2O]2

Tags

NGSS.HS-PS1-7

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

For the reaction H2 (g) + Br2 (g) ↔ 2 HBr (g), K = 4.0 x 10-2. For the reaction 2 HBr (g) ↔ H2 (g) + Br2 (g) K =:
a. 4.0 x 10-2
b. 5
c. 25
d. 2.0 x 10-1

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