BCHM 4115: Lectures 13-17

BCHM 4115: Lectures 13-17

University

15 Qs

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BCHM 4115: Lectures 13-17

BCHM 4115: Lectures 13-17

Assessment

Quiz

Biology

University

Practice Problem

Hard

NGSS
HS-LS1-6, HS-PS1-2

Standards-aligned

Created by

Maanya Sappa

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15 questions

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1.

OPEN ENDED QUESTION

2 mins • 8 pts

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On your own paper, draw the Hayworth projection for α-D-Fructofuranose

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Answer explanation

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2.

OPEN ENDED QUESTION

1 min • 6 pts

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  1. 1. Is this an aldose or a ketose?

  2. 2. Is this a D or L sugar?

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Answer explanation

  1. 1. An aldose, as indicated by the "CHO" group, which represents an aldehyde functional group. This means it will cyclize into a hemiacetal.

  1. 2. This is a D-sugar, specifically D-glucose. This is determined by the OH group on the highest-numbered stereocenter (C-5) pointing to the RIGHT.

3.

MULTIPLE CHOICE QUESTION

30 sec • 7 pts

Which one depicts a ceramide?

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Answer explanation

A ceramide consists of a sphingosine backbone connected to a fatty acid via an amide linkage. There are NO sugar moieties on a ceramide.

4.

OPEN ENDED QUESTION

3 mins • 10 pts

What makes cartilage so flexible?

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Answer explanation

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Cartilage is flexible due to proteoglycan–hyaluronate aggregates that are highly hydrated. Proteoglycans bind to long filaments of hyaluronic acid with the assistance of a link protein. When cartilage is compressed, water is squeezed out and is then reabsorbed when the stress is diminished, allowing for reversible hydration that cushions joints and supports flexibility.

5.

FILL IN THE BLANK QUESTION

45 sec • 5 pts

_ are a superfamily of plasma

immunity proteins that contain L-type lectin folds

and require Ca2+ ions for ligand binding.

Answer explanation

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6.

OPEN ENDED QUESTION

30 sec • 5 pts

Carbohydrates on proteins can be O-linked via these three residues:

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Answer explanation

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-Serine (S)

-threonine (T)

-Hyroxylysine (Hyl)

7.

OPEN ENDED QUESTION

1 min • 6 pts

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Draw the product of this reaction (on your own paper), and identify the resulting structure.

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Answer explanation

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OH + aldehyde = hemiacetal

OH + ketone = hemiketal

The hemiacetals/hemiketals are the structures that cyclize.

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