Two Step Equation Problems

Two Step Equation Problems

6th Grade

20 Qs

quiz-placeholder

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Two Step Equation Problems

Two Step Equation Problems

Assessment

Quiz

Mathematics

6th Grade

Hard

CCSS
7.EE.B.4A, HSA.CED.A.3, 6.EE.B.7

+1

Standards-aligned

Created by

Anthony Clark

FREE Resource

20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

This year, there are a total of 357 students in 6th grade. On Tuesday, sixteen classes had x 6th graders in them. There were a total of 15 students absent that day.


This situation can be represented by the equation:

357 = 16x+15

What would be the FIRST step in solving this equation?

Subtract 15 from both sides of the equation

Divide by 16 on both sides of the equation

Add 15 to both sides of the equation

Multiply by 16 on both sides of the equation

Tags

CCSS.HSA.REI.A.1

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Solve for x.


-7 + 4x = 37


Be sure to set up the problem on your paper and show ALL work on both sides of the equation! Don't forget to include your check step!

x=11

x=7.5

x=12

x=23

Tags

CCSS.7.EE.B.4A

3.

FILL IN THE BLANK QUESTION

1 min • 1 pt

Solve:


2x + 7 = 9


Type the NUMBER ONLY of your answer in the space provided. You do NOT need to include "x=" when you type your answer in the box.


Be sure to set up the problem on your paper and show ALL work on both sides of the equation! Don't forget to include your check step!

Tags

CCSS.7.EE.B.4A

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Jackie bought 2 pairs of ballet shoes and a tutu from Dance Works. She remembered that tutu was $38 and that the total cost was $148. Which equation can be used to find b, the cost of each pair of ballet shoes?

148 = 2b + 38

148 = 2b + 55

148 = 38 + b

148 = 38b

Tags

CCSS.HSA.CED.A.3

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

m=3

m=-4

m=-1

All real numbers

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

x=3

x=2

x=-2

x=1

7.

MATCH QUESTION

1 min • 1 pt

How would you solve each equation?

add 4 to both sides of =

x+4=12

divide both sides of = by 4

4x=12

subtract 4 from both sides of =

x-4=12

multiply both sides of = by 4

Tags

CCSS.6.EE.B.7

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