Describe this function.
Interpret Parts of an Exponential

Quiz
•
Mathematics
•
6th Grade
•
Hard
Anthony Clark
FREE Resource
8 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Exponential Growth
Exponential Decay
Linear Positive
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Describe the function.
Exponential Growth
Exponential Decay
Linear
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which scenario best matches the expression 12(1.015)t
A population of elephants begins with 12 elephants in a wildlife refuge 1975. The elephants increase in number by 1.5% each yaer.
A population of elephants begins with 12 elephants in a wildlife refuge 1975. The elephants decrease in number by 1.5% each yaer.
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The expression 12(1.015)t models the population of elephants in a wildlife refuge after t years since 1975.
What does the value 12 represent?
The predicted increase in number of elephants in the refuge each year.
The predicted decrease in number of elephants in the refuge each year.
The number of years it will take for the elephant population to stop increasing.
The initial amount of elephants in the park.
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
In an exponential function, what does the 'b' represent?
SLOPE
GROWTH FACTOR
Y-INTERCEPT
EXPONENT
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Classify the model as Exponential GROWTH or DECAY.
A=1200(.85)6
Growth
Decay
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The amount of ants in a colony, f, that is decaying can be modeled by f(x) = 800(.87)x, where x is the number of days since the decay started. Suppose f(20) = 49. Which of the following is true?
After 20 days, there are 49 ants in the colony.
After 49 days there are 20 ants in the colony.
The amount of ants times 20 is 49.
After 20 days the amount of ants remaining decreases by 49.
8.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Write an equation that models the following situation:
Samantha's hair was known to grow very rapidly. It began at a length of 6 in and grew at a rate of 14% a week.
y=6(0.14)x
y=6(1+14)x
y=6(1.14)x
y=6(0.86)x
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