Standard Form of a Circle

What is the center of the circle with this equation is (x+2)²+(y-4)²=41?

• (-2,41)

• (-2,4)

• (2,-4)

• (2,41)

What is the equation of a circle in standard form?

• ax²+bx+c=0

• (x-h)²+(x-k)²=r²

• (x-h)+(y-k)=r²

• x²+y²+ax+by+c=0

If the center of the circle is (1,1) and has the radius of 1, what is the equation?

• (x-1)²+(y-1)²=1

• (x-1)²+(y+1)²=1

• (x+1)²+(y-1)²=1

• (x-1)²+(y-1)²=-1

What is the center coordinate found in the equation in standard form?

• (x,y)

• (x²,y²)

• (h,k)

• (h,r)

Where is the radius in the equation of a circle in standard form?

• r

• x

• y

• h

If the center of the circle is at origin, the equation would be...

• x²+y²=r

• x²+y²=0

• x+y=r²

• x²+y²=r²

What is the correct graph for the equation (x-4)²+(y-2)²=25?

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What is the correct graph for the equation x²+y²=4?

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• Answer is in none of the given

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In the equation (x-4)²+(y-5)²=(2√14)², where would the radius lie?

• Radius would be around 14 units

• Radius would be around 56 units

• Radius would be between 7 and 8 units

• Radius would be between 6 and 7 units

Change the following equation to standard form
x²+y²-4x+12y-8=0

• (x+2)²+(y-6)²=48

• (x-2)²+(y+6)²=48

• (x-6)²+(y-2)²=48

• (x+2)²+(y-6)²=48