
Quiz on Gcf
Authored by Anthony Clark
Mathematics
6th Grade
Used 4+ times

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15 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the purpose of understanding GCF and LCM in mathematics?
To discuss number relationships in multiplication and division
To solve algebraic equations
To calculate area and perimeter
To measure angles
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the main focus of the lesson on Tuesday?
Finding common factors and multiples
Solving equations
Learning about geometry
Studying fractions
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What does GCF stand for?
Greatest Common Factor
Greatest Common Fraction
Greatest Common Formula
Greatest Common Function
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the greatest common factor (GCF) of 24 and 36?
2
6
12
18
Answer explanation
To find the GCF of 24 and 36, list the factors: 24 (1, 2, 3, 4, 6, 8, 12, 24) and 36 (1, 2, 3, 4, 6, 9, 12, 18, 36). The greatest common factor is 12, as it is the largest number in both lists.
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
If you have two numbers, 15 and 25, what is their GCF?
1
5
10
15
Answer explanation
The GCF (Greatest Common Factor) of 15 and 25 is 5, as it is the largest number that divides both without leaving a remainder. The factors of 15 are 1, 3, 5, 15 and for 25 are 1, 5, 25. The common factor is 5.
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
John has 18 apples and 24 oranges. He wants to make fruit baskets with the same number of each fruit in every basket. What is the greatest number of baskets John can make?
2
3
6
9
Answer explanation
To find the greatest number of baskets, we need the greatest common divisor (GCD) of 18 and 24. The GCD is 6. Thus, John can make 6 baskets with 3 apples and 4 oranges in each. However, he can also make 9 baskets with 2 apples and 2 oranges each.
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Sarah has two ribbons, one 12 feet and another 15 feet long. She wants to cut both ribbons into pieces of the same length without any leftover ribbon. What is the greatest length each piece can be?
foot
3 feet
6 feet
9 feet
Answer explanation
To find the greatest length for each piece, we need the greatest common divisor (GCD) of 12 and 15. The GCD is 3. However, the largest piece length that divides both ribbons without leftovers is 6 feet, as it fits into both lengths evenly.
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