Polynomial Translations

How is the amount of translation determined in a function?

• By the value of the coefficient multiplied to or divided from the function

• By the value of the exponent raised to the function

• By the value of the constant added to or subtracted from the function

• By the value of the logarithm applied to the function

What determines the amount of stretch?

• The value of the constant multiplied by the function

• The degree of the polynomial function

• The x-intercepts of the function

• The y-intercepts of the function

In Exercises 1-6, use the graphs of f and g to describe the transformation from the graph of f to the graph of g. The graph of g is a (a)   translation ___ units ____ of the graph of f.

• reflection

• x-axis

• vertical

• horizontal

• shrink

• stretch

In Exercises 1-6, use the graphs of f and g to describe the transformation from the graph of f to the graph of g. The graph of g is a ____ translation​ (a)   unit(s) ____ of the graph of f.

• 1

• 2

• 4

• 6

• 3

What transformations have occurred to get the graph of g(x) from the graph of f(x)?

• vertical shrink by a factor of 1/4,translation down 2 units

• vertical shrink by a factor of 1/4,translation right 2 units

• vertical stretch by a factor of 1/4,translation down 2 units

• vertical stretch by a factor of 1/4,translation right 2 units

Tags

CCSS.HSF.BF.B.3

• y = x³

• reflect and narrow

• left

• 1

• down

• reflect and flatten

• right

• up

• flatten

• narrow

Tags

CCSS.HSF.BF.B.3

What transformations has the function undergone?

• reflect over y, vertical compress by 2, right 5, up 1

• reflect over x, horizontal compression by 2, left 5, up 1

• reflect over x, vertical stretch by 2, right 5, up 1

• reflect over y, horizontal stretch by -2, right 5, up 1

Tags

CCSS.HSF.BF.B.3

In Exercises 1-6, use the graphs of f and g to describe the transformation from the graph of f to the graph of g. The graph of g is a ​​___ translation ​ (a)   units ____ of the graph of f.

• 4

• 2

• 1

• 5

• 6

• 0.5