Elimination Systems of Equations

Solve the following system of equations algebraically using Elimination Method.

• (1, 1)

• (3, 1)

• (-1, -1)

• (1, 3)

Solve the following system of equations algebraically using elimination method.

• (-3, 4)

• (3, 4)

• (3, -4)

• (-3, -3)

Solve the following system of equations algebraically using elimination method.

• No Solution

• (0, 0)

• (4, 4)

• (4, 0)

Solve the following system of equations algebraically using elimination method.

• (-6, 2)

• (6, 2)

• (2, 6)

• (2, -6)

Solve the system of equations using the elimination method:

3x + 2y - z = 6

2x - y + 3z = 4

4x + 3y + 2z = 9

• x = 4/5, y = 2, z = -3/5

• x = 0, y = 0, z = 0

• x = -2/3, y = 1/2, z = 1/4

• x = 1, y = 3, z = 2

Find the solution to the following system of equations using the elimination method: 2x + 3y - z = 5 3x - 2y + 4z = 7 4x + y + 2z = 3

• x = 2, y = -1, z = 1

• x = -2, y = 1, z = -1

• x = 1, y = 2, z = -1

• x = 3, y = -2, z = 2

Solve the system of equations using the elimination method: 3x + 2y - z = 6 2x - y + 3z = 4 4x + 3y + 2z = 9

• x = 4/5, y = 2, z = -3/5

• x = 0, y = 0, z = 0

• x = -2/3, y = 1/2, z = 1/4

• x = 1, y = 3, z = 2

Say you wanted to eliminate x from the system shown. How would you do it?

• Add the equations without doing any multiplication.

• Multiply the first equation by 2 and the second equation by 3, then add the equations.

• Multiply the first equation by negative 2 and the second equation by 3, then add the equations.

• Multiply the first equation by 3 and the second equation by negative 2, then add the equations.

Solve the system of equations.

• (10, 3)

• (6, 3)

• (15, 3)

• No solution

• Infinite Solution

Solve the system of equations.

• (11, 21)

• (3, 11)

• (11, -67)

• No solution

• Infinite solutions