Solve with Quadratic Formula with Complex Roots

Solve using the quadratic formula: f(x) = 2x² - 4x + 7

• x = (2 ± 2i√10)/2

• x = (4 ± √40)/4

• x = (2 ± i√10)√/2

• x = (2 ± 2i√40)/4

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

Solve x² - 5x + 10 = 0.

• x = (5 - i√15)/2, (5 + i√15)/2

• x = (5 - √15)/2, (5 + √15)/2

• x = (5 - i√65)/2, (5 + i√65)/2

• x = (5 - √65)/2, (5 + √65)/2

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

Solve for x:

3x² - 6x + 6 = 0

• x = 1± i

• x = 3, -6

• x = 4.8, 2.7

• Undefined

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

If the discriminant is negative, then the quadratic has:

• 1 Real Solution

• 2 Real Solutions

• Half a Solution

• 2 Complex (imaginary) Solutions

Tags

CCSS.HSA-REI.B.4B

Solve by the method of your choice

x² - 5x + 10 = 0

• (5 - i√15)/2  ,  (5 + i√15)/2

• (5 - √15)/2  ,  (5 + √15)/2

• (5 - i√65)/2  ,  (5 + i√65)/2

• (5 - √65)/2  ,  (5 + √65)/2

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

Solve x² - 5x + 10 = 0

• (5 - i√15)/2  ,  (5 + i√15)/2

• (5 - √15)/2  ,  (5 + √15)/2

• (5 - i√65)/2  ,  (5 + i√65)/2

• (5 - √65)/2  ,  (5 + √65)/2

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

x² - 5x + 10 = 0

• (5 - i√15)/2  ,  (5 + i√15)/2

• (5 - √15)/2  ,  (5 + √15)/2

• (5 - i√65)/2  ,  (5 + i√65)/2

• (5 - √65)/2  ,  (5 + √65)/2

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

Solve for x: 

(Hint: Use Quadratic Formula)

• x = {-4, -1}

• x = {-1, -4}

• x = {2+i, 2-i}

• x = {-2+i, -2-i}

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

Solve by ANY method you have learned: x²−2x+11=0

• 1±i√10

• 1±√10

• -1±i√10

• -1±√10

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

Hint: set equation = to 0.

• A

• B

• C

• D

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7