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Solving Quadratics from a Graph

Authored by Anthony Clark

Mathematics

9th Grade

CCSS covered

Solving Quadratics from a Graph
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15 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What are the roots of the function? 

{x|x = 4, -1}

(-4, 1)

{x|x = -4, 1}

(4, 0) (-1, 0)

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What are the roots of the function?

x = 4, -1

(-4, 1)

x = -4, 1

(4, 0) (-1, 0)

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which property allows you to solve an equation that looks like (x - 5)(2x + 8) = 0?

Associative Property of Multiplication

Zero Product Property

X-Intercept Property of Algebra 2

Commutative Property of Addition

Tags

CCSS.HSA-REI.B.4B

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What does it mean for the solutions to a quadratic equation to be 6 and 11?

The y-intercept is 6 and the x-intercept is 11.

The parabola is flipped upside-down.

The parabola crosses the x-axis at 6 and 11.

The parabola moved 6 units to the left and 11 units down from the origin.

Tags

CCSS.HSF-IF.C.7A

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Identify the domain and range of the function.

Domain: -6 ≤ x ≤ 2
Range: -3 ≤ y ≤ 5

Domain: All real number
Range: -3 ≤ y ≤ 5

Domain: All real numbers
Range: y ≥ -3

Domain: All real number
Range: y ≤ -3

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which of the following describes the graph of f(x)= x2 - 2x -15.

The graph has a maximum and has the x-intercepts of (-3, 0) and (5, 0)

The graph has a minimum and has the x-intercepts of (-3, 0) and (5, 0)

The graph has a maximum and has the x-intercepts of (3, 0) and (-5, 0)

The graph has a minimum and has the x-intercepts of (3, 0) and (-5, 0)

Tags

CCSS.HSF-IF.C.7A

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which if the following is an equation for a quadratic function that opens downward and has the vertex of (-4, 7)?

f(x)= -(x-4)2+7

f(x)= (x+4)2+7

f(x)= -(x+4)2+7

f(x)= (x-4)2+7

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