Solving Quadratics with Zero Method

• -2, 4
• -8
• ±8
• No real solution

Tags

CCSS.HSA-REI.B.4B

Find the zeros of this quadratic.

• b=4/5, b=3

• b=4, b=-3

• b=1/5, b=3

• b=4/5, b=-3

Tags

CCSS.HSA-REI.B.4B

• -4, 2
• -2, 4
• -16
• -4

Tags

CCSS.HSA-REI.B.4B

Suzie solves the equation below:
x² + 4x - 12 = 2
(x - 2)(x + 6) = 2, 
by setting x -2 = 0 and x + 6 = 0. 
Her solutions are x = 2 and x = -6.
Is Suzie correct? Why or why not?

• Yes, she factored correctly and then used the zero product property

• Yes, she factored correctly and then square rooted.

• No, she did factor correctly, but she can't use the zero product property as shown.

• No, she didn't factor correctly so the rest of her work is wrong. 

Tags

CCSS.HSA-REI.B.4B

• -6, -2
• -2, 6
• 2, 6
• -6, 2

Tags

CCSS.HSA-REI.B.4B

What are the zeros of this graph?

• x = {-4, 2}

• (-4, 0 ) and (2, 0)

• x = {-1, 0}

• (-1, 9 ) and (0, -8)

Tags

CCSS.HSF-IF.C.7A

What are the zeroes of this graph?

• x = -4 and 2

• x= -1 and 0

• x = 9 and -8

• x= 4 and -2

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

Find the root(s) of the function.

• x = {2, -3}

• x = {-2, -3}

• x = {-2, 3}

• x = {2, 3}

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

Tags

CCSS.HSF-IF.C.7A

What are the zeroes?

• x= 0 and x= -4

• x= 0 and x= 4

• y= 0

• x= 2 and x= -2

Tags

CCSS.HSA.APR.B.3