Solving Quadratics by Factoring

Solve for the values of x:
(x - 3)(x + 6) = 0

• { -3, -6 }

• { 3, -6 }

• { -3, -6 }

• { 3, 6 }

Tags

CCSS.HSA-REI.B.4B

Solve:

k² - 2k - 24 = 0

• k = -4, 6

• k = -4, -6

• k = -6, 1

• k = 4, -6

Tags

CCSS.HSA-REI.B.4B

Solve:

3x² + 18x +15 = 0

Hint: Factor GCF first.

• x = 3, 2

• x = 5, 1

• x = -5, -1

• x = -3, -2

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 2x - 24 = 0

• x = -6, x = 4

• x = 6, x = -4

• x = 12, x = -2

• x = 8, x = -3

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 9x + 20 = 0

• x = -2, x = -10

• x = -3, x = -4

• x = -4, x = -5

• x = -4, x = -6

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 7x + 12 = 0

• x = -2, x = -10

• x = -3, x = -4

• x = -4, x = -5

• x = -4, x = -6

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 13x + 12 = 0

• x = -1, x = -12

• x = -1, x = -24

• x = -2, x = -6

• x = -2, x = -12

Tags

CCSS.HSA-REI.B.4B

x² +0x - 49 = 0

• x = -7, x = 7

• x = -7

• x = 7

• x = -7, x = 1

Tags

CCSS.HSA-REI.B.4B

What is a method of checking your work when factoring?

• FOIL

• asking the teacher every time

• assume you're correct

• division

Factor
k² - 2k - 24

• (k+4)(k-6)

• (k+4)(k+6)

• (k+6)(k-1)

• (k-4)(k+6)