Factoring Quadratics When A > 0

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x

• Solve for x

• FOIL

• Set each binomial factor equal to zero

Solve for the values of x:
(x - 3)(x + 6) = 0

• { -3, -6 }

• { 3, -6 }

• { -3, -6 }

• { 3, 6 }

Factor and solve:

z² − 14z + 45 = 0

• z = 1, 45

• z = −1, 45

• z = −5, 9

• z = 5, 9

Solve using the Zero-Product Property.

(x + 4)(x − 3) = 0

• x = 4 and x = −3

• x = 2 and x = 1

• x = −4 and x = 3

• x = −2 and x = 1

Solve using the Zero-Product Property (x −11)(5x + 1) = 0

Factor and Solve: Remember the two numbers you choose when factoring, are not your solutions to the equation!

a² + 2a − 24 = 0

• a = −6, 4

• a = 6, −4

• a = 12, −2

• a = 8, −3

Factor and Solve: Remember the two numbers you choose when factoring, are not your solutions to the equation!

x² + 13x + 12 = 0

• x = −12, −1

• x = 12, 1

• x = 13, 1

• x = −13, −1

Which is the correct factoring and solutions? 2x^2+4x-16=0

• 2(x + 4)(x - 2) = 0;   x = -4, 2

• 2(x + 8)(x - 2) = 0;   x = -8, 2