Argument and Modulus for Complex Numbers
Quiz
•
Mathematics
•
12th Grade
•
Practice Problem
•
Hard
Standards-aligned
Anthony Clark
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20 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Calculate the modulus (R) and argument (θ) for z = -7 - 5i Give the argument between -π < θ < π.
R = 8.6, θ = -2.5 rad or -144.5°
R = 8.6, θ = 3.8 rad or 215.5°
R = 74, θ = 0.6 rad or 35.5°
R = 8.6 , θ = 4.1 rad or 234.5 °
Answer explanation
Tags
CCSS.HSN.CN.B.4
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Calculate the modulus (R) and argument (θ) for z = 3 - 7i. Give the argument between -π < θ < π.
R = √58, θ = -1.2 rad or -66.8°
R = 7.6, θ = 1.2 rad or 66°
R = √58, θ = 5.1 rad or 293.2°
R = 7.6 , θ = 1.98 rad or 113.2 °
Answer explanation
Tags
CCSS.HSN.CN.B.4
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Calculate the modulus (R) and argument (θ) for z = 4 + 9i Give the argument between -π < θ < π.
R = 9.05, θ = 1.99 rad or 114°
R = 9.8, θ = 1.2 rad or 66°
R = 97, θ = 1.2 rad or 66°
R = 9.8, θ = 5.13 rad or 294°
Answer explanation
Tags
CCSS.HSN.CN.B.4
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Calculate the modulus (R) and argument (θ) for z = -5 + 3i Give the argument between -π < θ < π.
R = 5.83, θ = 0.54 rad or 31°
R = 34, θ = 2.6 rad or 149°
R = 5.83, θ = 3.7 rad or 211°
R = 5.83, θ = 2.6 rad or 149°
Answer explanation
Tags
CCSS.HSN.CN.B.4
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Let w=-√3/2 + 1/2 i calculate the modulus and argument.
3, 120o
5, 270o
1, 150o
Not Possible
Tags
CCSS.HSN.CN.B.4
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Consider the complex number in the graph. Given that the argument must be between -π < θ < π, what can you say about the argument, θ?
θ is negative and -π < θ < -π/2
θ is negative and -π/2 < θ < 0
θ is positive and π/2 < θ < π
θ is positive and 0 < θ < π/2
Answer explanation
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Consider the complex number in the graph. Given that the argument must be between -π < θ < π, what can you say about the argument, θ?
θ is negative and -π < θ < -π/2
θ is negative and -π/2 < θ < 0
θ is positive and π/2 < θ < π
θ is positive and 0 < θ < π/2
Answer explanation
Tags
CCSS.HSN.CN.B.4
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