Solving Linear Quadratic Equations

Solve the quadratic equation by factoring and setting each factor = 0

:

5x² - 35x + 60 = 0

• x = 3, -4

• x = -3, 4

• x = 3, 4

• x = -3, -4

Tags

CCSS.HSA-REI.B.4B

Check all of the following situations where you could use the Quadratic Formula to solve an equation.

• When its highest exponent (degree) is 1

• When its highest exponent (degree) is 2

• When its highest exponent (degree) is 3

• When you cannot factor the quadratic

Tags

CCSS.HSA-REI.B.4B

• A
• B
• C
• D

Tags

CCSS.HSA.REI.C.7

Solve the system of linear and quadratic equations using substitution:
y = 5
y = 2x² - 16x + 29

• (6, 5) and (2, 5)

• (2, 6)

• (6, 2)

• (5, 6) and (5, 2)

Tags

CCSS.HSA.REI.C.7

• x=3

• x=-7

• x=0

• No Solution

• 1.5

• 6

• -6

• -1.5

Which of the following represents the first step in solving:

y = x² + 3x - 5

y = x + 3

• x² - 3x + 5 = x - 3

• x² + 3x - 5 = x + 3

• x² + 3x - 5 + x + 3 = 0

• x² + 3x - 5 = 0

Tags

CCSS.HSA-REI.B.4B

What are the solutions to the system:
y = x² + 3x - 5
y = x + 3

• (-4, 2) and (-1, 5)

• (-4, -1) and (2, 5)

• (2, -1 and (-4, 5)

• (-4, 1) and (2, -1)

Tags

CCSS.HSA.REI.C.7

Find the solution:
y = x² - 4x + 6
y = x + 2

• (3, 1) and (6, 4)

• (-1, 1) and (4, 2)

• (1, 3) and (4, 6)

• (1, 4) and (3, 6)

Tags

CCSS.HSA.REI.C.7

Determine the solution to the given linear-quadratic function.

• (0, 0)

• (3, 0)

• (2, -3)

• (-3, 2)

Tags

CCSS.HSA.REI.C.7