Midsegment and Angle Bisector

A segment joining two sides of a triangle at the midpoints.

• altitude

• perpendicular bisector

• midsegment

• angle bisector

A segment that bisects one of the angles of a triangle

• Angle Bisector

• Perpendicular Bisector

• Altitude

• Midsegment

The figure is an example of a(n) ...

• angle bisector

• perpendicular bisector

• median

• midsegment

The image show which point of concurrency

• circumcenter

• centroid

• incenter

• orthocenter

Tags

CCSS.HSG.C.A.3

• m∠GHK=26, m∠KHJ=26
• m∠GHK=26, m∠KHJ=52
• m∠GHK=52, m∠KHJ=52
• m∠GHK=52, m∠KHJ=26

Tags

CCSS.HSG.CO.C.9

• x=3/17
• x=9
• x=3
• x= -3

Tags

CCSS.HSG.CO.C.9

Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰ 
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
Step 5: 15⁰ + m∠2 = 30⁰
What is the justification for Step 5?

• Given

• Substitution

• Angle addition postulate

• Definition of congruent angles

Tags

CCSS.HSG.SRT.B.5

Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰ 
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
What is the justification for Step 4?

• Given

• Substitution

• Angle addition postulate

• Definition of congruent angles

Tags

CCSS.HSG.SRT.B.5

Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰ 
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
Step 5: 15⁰ + m∠2 = 30⁰
Step 6: m∠2 = 15⁰
Step 7: m∠1 = m∠2
Step 8: ∠1 ≅ ∠2
Step 9: AM bisects ∠LAN
What is the justification for Step 9?

• Symmetric property of congruence

• Definition of angle bisector

• Addition property of equality

• Definition of congruent angles

Tags

CCSS.HSG.CO.C.9

Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰ 
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
Step 5: 15⁰ + m∠2 = 30⁰
Step 6: m∠2 = 15⁰
What is the justification for Step 6?

• Subtraction property of equality

• Substitution

• Addition property of equality

• Definition of congruent angles

Tags

CCSS.HSG.SRT.B.5