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Angle Bisector Side Splitting

Quiz
•
Mathematics
•
10th Grade
•
Hard
Anthony Clark
FREE Resource
10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
angle bisector
perpendicular bisector
median
midsegment
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is a line segment or ray drawn from a vertex that divides the angle into two congruent angles?
Median of a Triangle
Altitude of a Triangle
Perpendicular Bisector of a side of a Triangle
Angle Bisector
Midpoint of a Line Segment
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
If DB bisects ∠ABC, then ∠ABD = ∠CBD.
Definition of Congruent Angles
Definition of Angle Bisector
Angle Addition Postulate
Definition of Right Angle
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the missing statement in the proof?
2m∠ABD = m∠ABD + m∠ABD
m∠ABD = m∠DBC
m∠ABC = m∠ABC
m∠ABD +m∠ABD = m∠ABD + m∠DBC
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the missing statement in the proof?
2m∠ABD=m∠ABD+m∠ABD
m∠ABD=m∠DBC
m∠ABC=m∠ABC
m∠ABD+m∠ABD=m∠ABD+m∠DBC
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
Step 5: 15⁰ + m∠2 = 30⁰
Step 6: m∠2 = 15⁰
Step 7: m∠1 = m∠2
Step 8: ∠1 ≅ ∠2
Step 9: AM bisects ∠LAN
What is the justification for Step 9?
Symmetric property of congruence
Definition of angle bisector
Addition property of equality
Definition of congruent angles
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
Step 5: 15⁰ + m∠2 = 30⁰
Step 6: m∠2 = 15⁰
What is the justification for Step 6?
Subtraction property of equality
Substitution
Addition property of equality
Definition of congruent angles
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