
Angle Bisector, Altitude, Median
Authored by Anthony Clark
Mathematics
10th Grade
CCSS covered

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20 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The figure is an example of a(n) ...
angle bisector
perpendicular bisector
median
midsegment
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which of the following segments represents an altitude?
BX
AZ
AC
BZ
Tags
CCSS.HSG.CO.C.10
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The dotted line represents a ?...
median
centroid
midsegment
midpoint
Tags
CCSS.HSG.CO.C.10
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which of the following segments represents a median?
BX
AZ
AC
BZ
Tags
CCSS.HSG.CO.C.10
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Given: PL is the angle bisector of <RPQ
What can you conclude by definition of angle bisector?
m<RPL = m<LPQ
<RPL + m<LPQ = m<RPQ
<RPQ is acute
m<RPQ = 90
Tags
CCSS.HSG.CO.C.9
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
Step 5: 15⁰ + m∠2 = 30⁰
Step 6: m∠2 = 15⁰
Step 7: m∠1 = m∠2
What is the justification for Step 7?
Subtraction property of equality
Transitive property of equality
Addition property of equality
Definition of congruent angles
Tags
CCSS.HSG.SRT.B.5
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
Step 5: 15⁰ + m∠2 = 30⁰
Step 6: m∠2 = 15⁰
Step 7: m∠1 = m∠2
Step 8: ∠1 ≅ ∠2
Step 9: AM bisects ∠LAN
What is the justification for Step 9?
Symmetric property of congruence
Definition of angle bisector
Addition property of equality
Definition of congruent angles
Tags
CCSS.HSG.CO.C.9
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