Solving for Quadratic Equations

Find the zeros of the quadratic equation y=4(x+9)²-36

• x=-9+√6 & x=-9-√6

• x=3 & x=-3

• x=-6 & x=-12

• so solution

Tags

CCSS.HSA-REI.B.4B

• Yes, she factored correctly and then used the zero product property

• No, she didn't factor correctly so the rest of her work is wrong.

• No, she did not set the equation equal to zero before factoring.

• Yes, she answered it correctly.

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(x + 2)(x - 3) = 0

• { 2, 3 }

• { -2, -3 }

• { 2, 3 }

• { -2, 3 }

Tags

CCSS.HSA-REI.B.4B

Tags

CCSS.8.EE.A.2

• x = 4

• x = 2

• x = - 2

• x= - 4

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• A. 1

• B. 3

• C. 1/3

• D. -1/3

Tags

CCSS.HSA-REI.B.4B

• a = 4, b = -8, c = 3

• a = 4, b =-8, c =-3

• a = 4, b = 8, c = 3

• a = 4, b = 8, c = -3

Solve by factoring

• -4, 2

• -2, 4

• -16

• -4

Tags

CCSS.HSA-REI.B.4B

Solve using the Quadratic Formula:

2x² + 2x − 12 = 0

• x = −2, 3

• x = 2, 3

• x = 2, −3

• x = −2, −3

Tags

CCSS.HSA-REI.B.4B

Solve by factoring. (HINT: Factor GCF 1st)

• x = 3, x = -6

• x = 0, x = 2

• x = 2, x = 3

• x = -2, x = 1

Tags

CCSS.HSA-REI.B.4B