Solutions to Quadratics

Find the zeros of this quadratic.

• b=4/5, b=3

• b=4, b=-3

• b=1/5, b=3

• b=4/5, b=-3

Tags

CCSS.HSA-REI.B.4B

Determine the values of

a, b, and c for

the quadratic equation:

4x² – 8x = 3

• a = 4, b = -8, c = 3

• a = 4, b =-8, c =-3

• a = 4, b = 8, c = 3

• a = 4, b = 8, c = -3

Suzie solves the equation below: x² + 4x - 12 = 2 (x - 2)(x + 6) = 2, by setting x -2 = 0 and x + 6 = 0. Her solutions are x = 2 and x = -6. Is Suzie correct? Why or why not?

• Yes, she factored correctly and then used the zero product property

• Yes, she factored correctly and then square rooted.

• No, she did factor correctly, but she can't use the zero product property as shown.

• No, she didn't factor correctly so the rest of her work is wrong.

Tags

CCSS.HSA-REI.B.4B

Solve by factoring.

-4y² + 24y - 36 = 0

• -3

• 7/2

• 4

• 3

Tags

CCSS.HSA-REI.B.4B

Solve

a² + 2a - 24 = 0

• a = -6, 4

• a = 6, -4

• a = 12, -2

• a = 8, -3

Tags

CCSS.HSA-REI.B.4B

What is the standard form for a Quadratic?

• ax²+ bx = - c

• x = -b ± √(b²-4ac) / 2a

• ax² + bx + c

• y = mx + b

What are the solutions?

• -2, 1

• 1, 2

• -1,2

• 0,-4

Solve the equation using square roots.

x² = 121

• 60.5

• ± 11

• ± 12

• 11

Tags

CCSS.8.EE.A.2

Solve by taking square roots:

k² - 6 = 43

• k = √37

• k = 37 or - 37

• k = 7, k = -7

• no solution

Tags

CCSS.HSA-REI.B.4B

Which of the following is the correct equation for the given graph?

• f(x) = (x - 2)² - 1

• f(x) = (x + 2)² - 1

• f(x) = -(x + 2)² - 1

• f(x) = -(x - 2)² - 1

Tags

CCSS.HSF-IF.C.7A