Solving Quadratic-Like Equations

Select the solutions to the equation

x² - x + 1 = 7

• x = 0

• x = 1

• x = -2

• x = 3

Select the solutions to the equation

2x² - 5x + 1 = 1

• x = 0.3

• x = 2.2

• x = 0

• x = 2.5

Select the solutions to the equation

x² + 3x + 2 = 11

• x = -4.9

• x = 1.9

• x = -1

• x = -2

Select the solutions to the equation

x² - 6x + 6 = -1

• x = 1.6

• x = 4.4

• x = 2

• x = 4

The diagram shows part of the graph of y = x² – 4x + 1

Which option shows the straight line that you would draw on the graph to solve the equation for the solutions of x² – 2x - 3 = 0?

• y = 2x - 4

• y = -2x - 4

• y = -2x + 4

• y = 2x + 4

The diagram shows part of the graph of y = x² – 4x + 1

Use the graph to solve the quadratic x² – 2x - 3 = 0?

Select all the values of x that are solutions.

• x = - 1

• x = 2

• X = 3

• y = -3

The diagram shows part of the graph of y = x² – 4x + 5

Which option shows the straight line that you would draw on the graph to solve the equation for the solutions of x² – 6x + 8 = 0?

• y = 2x - 3

• y = -2x - 3

• y = -2x + 3

• y = 2x + 3

The diagram shows part of the graph of y = x² – 4x + 5

Use the graph to solve the quadratic x² – 6x + 8 = 0

Select all the values of x that are solutions.

• x = - 2

• x = 2

• x = 4

• y = -3

By drawing the graph of y = x²−4 (on a graphical calculator) solve x²−x −12 = 0

• x = -3, or x = 4

• x = 5, or x = 12

• x = 3, or x = -4

• x = -5, or x = 12

Identify the straight line you would have to draw in order to use the quadratic graph y = x²−4 to solve the equation x²−x −12 = 0

• y = x + 8

• y = 2x - 5

• y = x - 8

• y = 2x + 5