Surface Area of Prisms, Cones and Cylinders

Surface Area of Prisms, Cones and Cylinders

8th Grade

20 Qs

quiz-placeholder

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Surface Area of Prisms, Cones and Cylinders

Surface Area of Prisms, Cones and Cylinders

Assessment

Quiz

Mathematics

8th Grade

Hard

CCSS.7.G.B.6, 8.7.B, CCSS.6.G.A.4

Standards-aligned

Created by

Anthony Clark

FREE Resource

20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Find the total surface area of the prism.

161 square feet

1,700 square feet

75 square feet

186 square feet

Tags

CCSS.7.G.B.6

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Find the surface area of this figure.

Round to the nearest hundredth.

1981.9 sq m

1525.9 sq m

1468.8 sq m

1350.2 sq m

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Find the surface area of this figure.

Round to the nearest hundredth.

84.44 sq in

25.25 sq in

104.62 sq in

56.52 sq in

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which example requires you to find the surface area?

Finding out how much water will fill a cylinder

Finding out how much wrapping paper is needed to cover a present

Finding the amount a container can hold

Finding out how much wood is needed to build a fence in your back yard.

5.

DROPDOWN QUESTION

1 min • 1 pt

Media Image

The dimensions of a triangular prism and a cylinder are shown below. Choose the correct answer from each drop-down menu to complete the statements. The total surface area of the triangular prism measures ​ (a)   The total surface area of the cylinder measures approximately ​ (b)  

Tags

8.7.B

6.

MATH RESPONSE QUESTION

1 min • 1 pt

A rectangular prism has a length of 10 cm, a width of 6 cm, and a height of 4 cm. What is the total surface area of the prism?

Mathematical Equivalence

ON

Tags

CCSS.7.G.B.6

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Jesse needs to wrap the present shown below. How much wrapping paper would he need?

Which formula can be used to find the surface area of the present?

S=2B + Ph

S=2πrh+2πr2

S=Ph

V=Bh

Tags

CCSS.7.G.B.6

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