Solving Systems Using Elimination

• (4, -2)

• (-2, 4)

• (2, 4)

• (2, -4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

(-3, 2)

(3, 2)

(-2, 3)

(2, -3)

• (-3, 2)

• (3, 2)

• (-2, 3)

• (2, -3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• (1, 4)

• (4, 1)

• (1, -4)

• (-4, 1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• (-5, -9)

• (9, 5)

• (5, 9)

• (-9, -5)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following system of equations using the elimination method.

• infinite solutions

• (0, -2)

• no solutions

• (0, 2)

Tags

CCSS.8.EE.C.8B

Solve the system of equations using elimination.

• f = -2, g = 1

• f = -1, g = 2

• f = 1, g = -2

• f = 2, g = -1

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Find the solution to the following system of equations using the elimination method: 2x + 3y - z = 5 3x - 2y + 4z = 7 4x + y + 2z = 3

• x = 2, y = -1, z = 1

• x = -2, y = 1, z = -1

• x = 1, y = 2, z = -1

• x = 3, y = -2, z = 2

Solve the following system of equations using the elimination method:

• (-2, 1)

• no solutions

• (-2, 0)

• (-1, -3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations using the elimination method:

3x + 2y - z = 6

2x - y + 3z = 4

4x + 3y + 2z = 9

• x = 4/5, y = 2, z = -3/5

• x = 0, y = 0, z = 0

• x = -2/3, y = 1/2, z = 1/4

• x = 1, y = 3, z = 2

Say you wanted to eliminate x from the system shown. How would you do it?

• Add the equations without doing any multiplication.

• Multiply the first equation by 2 and the second equation by 3, then add the equations.

• Multiply the first equation by negative 2 and the second equation by 3, then add the equations.

• Multiply the first equation by 3 and the second equation by negative 2, then add the equations.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6