Method System of Equations

Solve using Elimination: 3x+y=9 and 5x+4y=22

• (2,3)

• (3,2)

• (0,2)

• Impossible to solve.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

True or False: When using elimination, you need to have the variables lined up.

• True

• False

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

A customer at a store paid $64 for 3 large candles and 4 small candles. At the same store, a second customer paid $68 for 1 large candle and 8 small candles. The price of each large candle is the same, and the price of each small candle is the same. Which system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y?

• 4y = 3x + 64

  8y = x + 68

• 4y = 3x + 64

  8y = x + 60

• 3x + 4y = 64

  x + 8y = 68

• 3x + 4y = 64

  x + 8y = 60

Tags

CCSS.HSA.CED.A.3

Solve the system. 

• (5, -6, 3)

• (2, 3, -1)

• (-4, 2, 5)

• No Solution

A customer at a store paid $64 for 3 large candles and 4 small candles. At the same store, a second customer paid $4 more than the first customer for 1 large candle and 8 small candles. The price of each large candle is the same, and the price of each small candle is the same. Which system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y?

• 4y = 3x + 64

  8y = x + 68

• 4y = 3x + 64

  8y = x + 60

• 3x + 4y = 64

  x + 8y = 68

• 3x + 4y = 64

  x + 8y = 60

Tags

CCSS.HSA.CED.A.3

Solve the system.

• (2, -2, 3)

• (2, 1, 4)

• (-2, 2, -3)

• No Solution

Solve the following system of equations.

• (15, 120, 45)

• (120, 15, 45)

• (15, -15, 0)

• (-15, 15, 0)

A customer at a store paid $64 for 3 large candles and 4 small candles. At the same store, a second customer paid $4 more than the first customer for 1 large candle and 8 small candles. The price of each large candle is the same, and the price of each small candle is the same. Which system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y?

• 4y = 3x + 64

  8y = x + 68

• 4y = 3x + 64

  8y = x + 60

• 3x + 4y = 64

  x + 8y = 68

• 3x + 4y = 64

  x + 8y = 60

Tags

CCSS.HSA.CED.A.3

Solve using elimination: 3y+2x=6 and 5y−2x=10

• (0,2)

• (2,0)

• (0,8)

• (8,0)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system by using the substitution method

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6