Geometry Unit 10 Circles

How do you find 4?

• 4=180-HJ

• 4=2(HJ)

• 4=1/2(LK-HJ)

• 4=1/2(HJ-LK)

Answer explanation

4=1/2(HJ-LK) because it is a vertex outside of a circle

Tags

CCSS.HSG.C.A.2

Which of the following is the standard equation of a circle HINT!! (x, y) = any point, center = (h, k) radius = (r)

• (x+h)^2+(y+k)^2=r^2

• (x-h)^2+(y+k)^2=r^2

• (x+h)^2+(y-k)^2=r^2

• (x-h)^2+(y-k)^2=r^2

Answer explanation

Yes, both signs are swapped for the center in standard equation.

Tags

CCSS.HSG.GPE.A.1

How would you find 1?

• 1=AB

• 1=180-AB

• 1=1/2AB

• 1=360-AB-180

Answer explanation

Yes, because it is a central angle. Central angle measures are equal to arc measures.

Tags

CCSS.HSG.C.A.2

Find measure of 2

• m2=AB

• m2=AB-180

• m2=AB/2

• m2=AB-ABC

Answer explanation

m2=AB/2 because it is an inscribed angle

Tags

CCSS.HSG.C.A.2

What is the equation of the circle shown in the graph?

Mathematical Equivalence

ON

Tags

CCSS.HSG.GPE.A.1

Label each of the following.

d

c

b

a

Secant

Radius

Tangent

Chord

Match the items to the proper parts of this image

a

b

c

Secant

Tangent Line

Diameter

Find 3

• 3=180-DE

• 3=1/2(DE+FG)

• 3=1/2(DG+FE)

• 3=180-FE

Answer explanation

3=1/2(DE+FG) because it is a vertex inside the circle

Tags

CCSS.HSG.C.A.2

a*b =...

• c*d

• c(cd)

• b*d

• a(cd)

Answer explanation

Two chords, product of segments of one chord = product of segments of the other.

Tags

CCSS.HSG.C.A.2

r^2=

• s-180

• t/s

• r/s

• s*t

Answer explanation

s*t because it is a tangent and secant

Tags

CCSS.HSG.C.A.2